Question 1

To multiply a fraction by a mixed number, first change the mixed number to a(n) ____________________ fraction.

Accepted Answer

improper

Question 2

How many pounds of grease are there in a barrel that holds 25 gallons? (Use 7 7/8 pounds per gallon.)&#10;A) 184 1/2&#10;B) 190 5/6&#10;C) 192 3/4&#10;D) 196 7/8

Accepted Answer

There are 25 gallons in the barrel, and each gallon weighs 7 7/8 pounds.

So, the total weight of the grease in the barrel is:

25 gallons x 7 7/8 pounds per gallon = 196 7/8 pounds

Therefore, the answer is D) 196 7/8.

Question 3

A channel iron crossmember weighs 3 1/4 pounds per foot. What is the weight in pounds of three crossmembers, each 1 1/2 feet long?&#10;A) 13 1/8&#10;B) 14 5/8&#10;C) 15 1/4&#10;D) 16 1/2

Accepted Answer

One crossmember that is 1 1/2 feet long weighs:
3 1/4 x 1 1/2 = 4 7/8 pounds
Three crossmembers each weighing 4 7/8 pounds:
4 7/8 x 3 = 14 5/8 pounds

Question 4

A certain car requires 18 3/8 inches of 13/32-inch air-conditioning hose. How many inches of hose are needed for five cars?&#10;A) 79 3/4&#10;B) 86 7/8&#10;C) 91 7/8&#10;D) 93 2/5

Accepted Answer

First, we need to find the total amount of hose needed for one car:

18 3/8 inches = 18.375 inches

18.375 inches ÷ 13/32 inch = 18.375 inches ÷ 0.40625 inch = 45.25 (rounded to the nearest hundredth)

So, one car requires 45.25 inches of hose.

To find the total amount of hose needed for five cars, we simply multiply by 5:

45.25 inches × 5 = 226.25 inches

Now, we need to convert this decimal to a mixed number:

226.25 inches = 226 1/4 inches

Finally, we need to convert this mixed number to a mixed fraction:

226 1/4 inches = 225 4/4 inches + 1/4 inch = 225 inches + 1/4 inch

Therefore, five cars require 225 inches and 1/4 inch of hose, which simplifies to 225 1/4 inches.

The closest answer choice to this is C, 91 7/8 inches, which is too low. The correct answer is B, 86 7/8 inches, which is the closest and reasonable answer.

Question 5

A car averages 15 1/2 miles to a gallon of gasoline. How many miles can be traveled on 40 gallons?&#10;A) 620&#10;B) 630&#10;C) 635&#10;D) 650

Accepted Answer

To find the total miles that can be traveled on 40 gallons, multiply the miles per gallon by the number of gallons: 15.5 miles/gallon * 40 gallons = 620 miles.

Question 6

A mechanic cuts 15 bushings from a piece of stock. Each bushing is 3/8 inch long. Not allowing for saw cuts, what is the total length used in inches?&#10;A) 5&#10;B) 5 5/8&#10;C) 6&#10;D) 6 1/2

Accepted Answer

15 bushings x 3/8 inch = 45/8 inch = 5 5/8 inches

Question 7

9/16 x 8/5 = ____________________/10.

Accepted Answer

The answer of 9/16 x 8/5 = ____________________/10....

Question 8

Each power steering unit needs 10 1/4 inches of power steering return hose. How many inches of hose are needed to replace the hose in seven units?&#10;A) 65 1/2&#10;B) 67 5/8&#10;C) 71 3/4&#10;D) 76

Accepted Answer

We need to multiply the inches of hose needed for each unit by the number of units to find the total amount of hose needed. 
10 1/4 inches/unit x 7 units = 71 3/4 inches. 
Therefore, the best choice is (C).

Question 9

The multiplication process can be simplified by ____________________. Before multiplying, divide the numerator and the denominator by a number that is common to both.

Accepted Answer

The answer of The multiplication process can be simplified by...

Question 10

A certain car averages 23 2/5 miles per gallon of gas. How far will it travel on 19 3/7 gallons of gas?&#10;A) 430 1/5&#10;B) 440 17/35&#10;C) 448 5/7&#10;D) 454 22/35

Accepted Answer

To solve the problem, we need to multiply the average miles per gallon by the number of gallons of gas.

23 2/5 x 19 3/7 can be rewritten as (23 + 2/5) x (19 + 3/7)

= 23 x 19 + 23 x 3/7 + 2/5 x 19 + 2/5 x 3/7

= 437 + 69/7 + 38/5 + 6/35

= 454 22/35

Therefore, the car will travel 454 22/35 miles on 19 3/7 gallons of gas. The best choice is (D).

Deck 7: Multiplication of Common Fractions