Question 1

Revenue chain is &#8230;&#8230;.. Feet long & consist of &#8230;&#8230;&#8230;.. Links.&#10;A)50& 20&#10;B)33 & 16&#10;C)50& 70&#10;D)All of above

Accepted Answer

33 & 16&#10;

Question 2

Which method is simplest method of plane tabling?&#10;A)Method of radiation&#10;B)Method of intersection&#10;C)Method of traversing&#10;D)Method of resection

Accepted Answer

The method of radiation is the simplest method of plane tabling because it involves directly plotting points from a single station by measuring angles and distances, making it straightforward and easy to implement.

Question 3

The horizontal distance between any two consecutive contours is known as&#8230;..&#10;A)Horizontal distance&#10;B)Lateral distance&#10;C)Length&#10;D)Horizontal equivalent

Accepted Answer

The horizontal distance between any two consecutive contours is referred to as the "horizontal equivalent." This term is used in topography and cartography to describe the distance on a map between two points that are at the same elevation, indicating the flat, horizontal distance between these contour lines.

Question 4

Contour interval depends on:&#10;A)The nature of ground&#10;B)The scale of map&#10;C)The purpose and extent of survey&#10;D)All of above

Accepted Answer

Contour interval depends on the nature of the ground, the scale of the map, and the purpose and extent of the survey, as these factors determine the level of detail and accuracy required.

Question 5

Correction required for curvature for a distance of 150&#176; m is&#8230;.&#10;A)0.50 m&#10;B)1m&#10;C)0.176 m&#10;D)0.30 m

Accepted Answer

The correction for curvature (C) for a distance (D) measured along the surface of the Earth can be calculated using the formula C = 0.0785 * D^2, where D is in kilometers. For a distance of 150 meters (0.15 kilometers), C = 0.0785 * (0.15)^2 = 0.00176 kilometers or 0.176 meters.

Question 6

Correction required for refraction for a distance of 10 km is&#8230;.&#10;A)7.85 m&#10;B)1.22 m&#10;C)3.33 m&#10;D)5 m

Accepted Answer

The answer of Correction required for refraction for a distance...

Question 7

Combined correction for curvature and refraction for 800 m distance is&#8230;&#8230;&#10;A)0.0431m&#10;B)1m&#10;C)0.5m&#10;D)2 m

Accepted Answer

The combined correction for curvature and refraction for a distance is calculated using the formula: $C = -0.0673 \times D^2$, where $C$ is the correction in meters and $D$ is the distance in kilometers. For 800 m (or 0.8 km), the calculation is $C = -0.0673 \times (0.8)^2 = -0.0431m$. This correction accounts for both the earth's curvature and the atmospheric refraction, which slightly bends the light downwards.

Question 8

1&#176;Which method is less tedious and more rapid for calculation of RL?&#10;A)HI method&#10;B)Rise & fall method&#10;C)none&#10;D)all

Accepted Answer

The HI (Height of Instrument) method is less tedious and more rapid for calculation of Reduced Level (RL) compared to the Rise & Fall method because it involves simpler calculations and fewer steps.

Question 9

Which method is more accurate for calculation of RL?&#10;A)HI method&#10;B)Rise & fall method&#10;C)none&#10;D)all

Accepted Answer

The Rise & Fall method is considered more accurate for the calculation of Reduced Level (RL) because it involves checking the arithmetic by balancing the total rise and total fall, which helps in minimizing errors.

Question 10

Which method is suitable for profile levelling?&#10;A)HI method&#10;B)Rise & fall method&#10;C)none&#10;D)all

Accepted Answer

The HI (Height of Instrument) method is suitable for profile levelling as it is efficient for determining elevations along a line, which is essential in creating profiles.

Question 11

Which method is suitable for precise levelling?&#10;A)HI method&#10;B)Rise & fall method&#10;C)none&#10;D)all

Accepted Answer

The answer of Which method is suitable for precise levelling?&#10;A)HI...

Question 12

Full name of M.S.L is&#8230;..&#10;A)Mean sea level&#10;B)Mean Saturation level&#10;C)Mean Standard level&#10;D)None of this

Accepted Answer

The answer of Full name of M.S.L is&#8230;..&#10;A)Mean sea level&#10;B)Mean...

Question 13

In which telescope length is comparatively less?&#10;A)Internal focusing telescope&#10;B)External focusing telescope&#10;C)none&#10;D)all

Accepted Answer

The answer of In which telescope length is comparatively less?&#10;A)Internal...

Question 14

Least count of self-reading staff is&#8230;..&#10;A)5mm&#10;B)0.5mm&#10;C)none&#10;D)all

Accepted Answer

The answer of Least count of self-reading staff is&#8230;..&#10;A)5mm&#10;B)0.5mm&#10;C)none&#10;D)all...

Question 15

Least count of target staff is&#8230;..&#10;A)5mm&#10;B)0.5mm&#10;C)none&#10;D)all

Accepted Answer

The answer of Least count of target staff is&#8230;..&#10;A)5mm&#10;B)0.5mm&#10;C)none&#10;D)all...

Question 16

If magnetic bearing of line AB is 279' and magnetic declinations is 7'W.Find the true bearing.&#10;A)279'&#10;B)210-&#10;C)211'&#10;D)272'

Accepted Answer

The answer of If magnetic bearing of line AB is...

Question 17

If FB of line PQ is N 35' W and FB of line QR is S 40&#176; W, find angle PQR.&#10;A)80&#10;B)75&#10;C)95&#10;D)85

Accepted Answer

The answer of If FB of line PQ is N...

Question 18

Fore bearing of line Ab is S35'W calculate its back bearing.&#10;A)N35'E&#10;B)S40&#176;W&#10;C)E35'W&#10;D)E35'N

Accepted Answer

The answer of Fore bearing of line Ab is S35'W...

Question 19

Back bearing of line Ab is 185', calculate its fore bearing.&#10;A)7'&#10;B)10'&#10;C)5'&#10;D)9'

Accepted Answer

The answer of Back bearing of line Ab is 185',...

Question 20

Convert N30&#176;15'E into WCB.&#10;A)32'15'&#10;B)70'15'&#10;C)30&#176;15'&#10;D)210'15'

Accepted Answer

The answer of Convert N30&#176;15'E into WCB.&#10;A)32'15'&#10;B)70'15'&#10;C)30&#176;15'&#10;D)210'15'...

Question 21

Convert 242'45&#176; into QB.&#10;A)N 42'30&#176; E&#10;B)S 62'45&#176; W&#10;C)N 31'50&#176; W&#10;D)S 53'45&#176; E

Accepted Answer

The answer of Convert 242'45&#176; into QB.&#10;A)N 42'30&#176; E&#10;B)S 62'45&#176;...

Deck 4: Surveying and Levelling: Part C