Deck 15: Thermodynamics

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سؤال
On a PV\mathrm{PV} diagram where pressure is in atmospheres and V\mathrm{V} is in liters the area is measured in liter-atmospheres. What is the number of Joules in 1.00 liter-atmosphere?

A) 101.3
B) 15.7
C) 65.2
D) 83.1
E) 22.4
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سؤال
Using 0.0200 mol0.0200 \mathrm{~mol} of an ideal monatomic gas, an isochoric process from state A(230kPa,1.0 L\mathrm{A}(230 \mathrm{kPa}, 1.0 \mathrm{~L} ) to B(98\mathrm{B}(98 kPa,1.0 L\mathrm{kPa}, 1.0 \mathrm{~L} ) results in what change in internal energy?

A) 375 J-375 \mathrm{~J}
B) 200 J-200 \mathrm{~J}
C) +200 J+200 \mathrm{~J}
D) +375 J+375 \mathrm{~J}
سؤال

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at a constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . How much heat is absorbed by the gas?

A) 288 J288 \mathrm{~J}
B) 389 J389 \mathrm{~J}
C) 544 J544 \mathrm{~J}
D) 436 J436 \mathrm{~J}

سؤال

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . What is the change of volume of the gas in this process?

A) 0.86 L0.86 \mathrm{~L}
B) 1.88 L1.88 \mathrm{~L}
C) 2.09 L2.09 \mathrm{~L}
D) 1.23 L1.23 \mathrm{~L}

سؤال

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . What is the work done by the gas during this expansion?

A) 172 J172 \mathrm{~J}
B) 125 J125 \mathrm{~J}
C) 159 J159 \mathrm{~J}
D) 102 J102 \mathrm{~J}

سؤال

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . From the first law, calculate the change of internal energy of the gas in this process.

A) 365 J365 \mathrm{~J}
B) 155 J155 \mathrm{~J}
C) 291 J291 \mathrm{~J}
D) 312 J312 \mathrm{~J}

سؤال
A very efficient engine has the following characteristics-combustion =1,900C=1,900^{\circ} \mathrm{C} , exhaust =430C,5.0×=430^{\circ} \mathrm{C}, 5.0 \times 10610^{6} cal of fuel produces 1.4×107 J1.4 \times 10^{7} \mathrm{~J} of work in one hour. What is the output in hp\mathrm{hp} ? (1hp=745.7 W)(1 \mathrm{hp}=745.7 \mathrm{~W})

A) 7.3hp7.3 \mathrm{hp}
B) 5.2hp5.2 \mathrm{hp}
C) 8.1hp8.1 \mathrm{hp}
D) 6.3hp6.3 \mathrm{hp}
سؤال
A heat engine has an efficiency of 25.0%25.0 \% and a power output of 600 W600 \mathrm{~W} . What is the rate of heat input?

A) 2.4 kW2.4 \mathrm{~kW} .
B) 1.8 kW1.8 \mathrm{~kW} .
C) 3.0 kW3.0 \mathrm{~kW} .
D) 2.0 kW2.0 \mathrm{~kW} .
سؤال
A refrigerator uses 40.0 J40.0 \mathrm{~J} of work to extract 90.0 J90.0 \mathrm{~J} from a heat reservoir at 0.00C0.00^{\circ} \mathrm{C} . What is the coefficient of performance for the refrigerator?

A) 2.05
B) 2.85
C) 2.25
D) 1.60
سؤال
120 J120 \mathrm{~J} of heat flows by thermal conduction from 100C100^{\circ} \mathrm{C} to 0.00C0.00^{\circ} \mathrm{C} . What is the net change in entropy for this process?

A) 0.034 J/K0.034 \mathrm{~J} / \mathrm{K}
B) 0.118 J/K0.118 \mathrm{~J} / \mathrm{K}
C) 0.338 J/K0.338 \mathrm{~J} / \mathrm{K}
D) 0.201 J/K0.201 \mathrm{~J} / \mathrm{K}

سؤال

When 1.000 kg1.000 \mathrm{~kg} of ice melts, 33.00×104 J/kg33.00 \times 10^{4} \mathrm{~J} / \mathrm{kg} of heat are needed. What is the entropy change of the ice in the melting process?

A) 1,684 J/K1,684 \mathrm{~J} / \mathrm{K}
B) 1,209 J/K1,209 \mathrm{~J} / \mathrm{K}
C) 758.0 J/K758.0 \mathrm{~J} / \mathrm{K}
D) 2,316 J/K2,316 \mathrm{~J} / \mathrm{K}

سؤال
When 2.000 kg2.000 \mathrm{~kg} of water evaporates, 22.60×105 J/kg22.60 \times 10^{5} \mathrm{~J} / \mathrm{kg} of heat are needed. What is the entropy change of the water in the boiling process?

A) 6,750 J/K6,750 \mathrm{~J} / \mathrm{K}
B) 12,120 J/K12,120 \mathrm{~J} / \mathrm{K}
C) 5,844 J/K5,844 \mathrm{~J} / \mathrm{K}
D) 8,566 J/K8,566 \mathrm{~J} / \mathrm{K}
سؤال
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(\mathrm{T}_{\mathrm{F}} / \mathrm{T}_{\mathrm{i}}\right) , where m\mathrm{m} is the mass of the sample, c\mathrm{c} is the specific heat of the sample, and TF\mathrm{T}_{\mathrm{F}} and Ti\mathrm{T}_{\mathrm{i}} are the final and initial temperatures, respectively. What is the change in entropy when 10.0 grams of lead with a specific heat of 0.452 J/gK0.452 \mathrm{~J} / \mathrm{g} \mathrm{K} is heated from 10.0C10.0^{\circ} \mathrm{C} to 50.0C50.0^{\circ} \mathrm{C} ?

A) 0.90 J/K0.90 \mathrm{~J} / \mathrm{K}
B) 0.30 J/K0.30 \mathrm{~J} / \mathrm{K}
C) 0.60 J/K0.60 \mathrm{~J} / \mathrm{K}
D) 0.45 J/K0.45 \mathrm{~J} / \mathrm{K}
سؤال
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(\mathrm{T}_{\mathrm{F}} / \mathrm{T}_{\mathrm{i}}\right) , where m\mathrm{m} is the mass of the sample, c\mathrm{c} is the specific heat of the sample, and TF\mathrm{T}_{\mathrm{F}} and Ti\mathrm{T}_{\mathrm{i}} are the final and initial temperatures, respectively. What is the change in entropy when 20.0 grams of aluminum with a specific heat of 0.900 J/gK0.900 \mathrm{~J} / \mathrm{g} \mathrm{K} is cooled from 60.0C60.0^{\circ} \mathrm{C} to 10.0C10.0^{\circ} \mathrm{C} ?

A) +2.93 J/K+2.93 \mathrm{~J} / \mathrm{K}
B) 0.00 J/K0.00 \mathrm{~J} / \mathrm{K}
C) +2.50 J/K+2.50 \mathrm{~J} / \mathrm{K}
D) 2.93 J/K-2.93 \mathrm{~J} / \mathrm{K}
سؤال
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(T_{F} / T_{i}\right) , where mm is the mass of the sample, cc is the specific heat of the sample, and TFT_{F} and TiT_{i} are the final and initial temperatures, respectively. What is the change in entropy when 20.0 grams of aluminum with a specific heat of 0.900 J/gK0.900 \mathrm{~J} / \mathrm{g} \mathrm{K} is heated from 10.0C10.0^{\circ} \mathrm{C} to 60.0C60.0^{\circ} \mathrm{C} ?

A) 2.93 J/K-2.93 \mathrm{~J} / \mathrm{K}
B) +2.50 J/K+2.50 \mathrm{~J} / \mathrm{K}
C) +2.93 J/K+2.93 \mathrm{~J} / \mathrm{K}
D) 0 J/K0 \mathrm{~J} / \mathrm{K}
سؤال
2.00 moles of an ideal gas freely expands from 1.50 liters to 4.00 liters. The change in entropy in the expansion is

A) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
B) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
سؤال
1.50 moles of an ideal gas freely expands from 1.00 liter to 4.50 liters. The change in entropy of the gas in the expansion is

A) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
B) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
سؤال
One mole of an ideal gas freely expands from 1.00 liter to 2.00 liters. The change in entropy of the gas in the expansion is

A) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
B) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
سؤال
A system in a certain macrostate has 1.2×1031.2 \times 10^{3} microstates. Through some process, the system changes the number of microstates to 3×1043 \times 10^{4} . What is the change in entropy for the process?

A) 1.1×1023 J/K1.1 \times 10^{-23} \mathrm{~J} / \mathrm{K}
B) 4.4×1023 J/K4.4 \times 10^{-23} \mathrm{~J} / \mathrm{K}
C) 5.6×1023 J/K5.6 \times 10^{-23} \mathrm{~J} / \mathrm{K}
D) 2.1×1023 J/K2.1 \times 10^{-23} \mathrm{~J} / \mathrm{K}
سؤال
On a PV diagram, what kind of process is represented by a horizontal line with an arrow left to right?

A) Isobaric compression
B) Isothermal compression
C) Adiabatic process
D) Isothermal expansion
E) Isobaric expansion
F) Isochoric process
سؤال
On a PV diagram, what kind of process is represented by a vertical line with an arrow pointing downward?

A) Isobaric compression
B) Isothermal expansion
C) Isothermal compression
D) Adiabatic process
E) Isochoric process
F) Isobaric expansion
سؤال
For a system undergoing an adiabatic process,

A) Q=ΔUQ=\Delta U
B) Q=W\mathrm{Q}=-\mathrm{W}
C) Q=ΔU\mathrm{Q}=-\Delta \mathrm{U}
D) Q=W\mathrm{Q}=\mathrm{W}
E) Q=0\mathrm{Q}=0
سؤال
For a system undergoing an isothermal process,

A) Q=W\mathrm{Q}=-\mathrm{W}
B) Q=ΔU\mathrm{Q}=-\Delta \mathrm{U}
C) Q=W\mathrm{Q}=\mathrm{W}
D) Q=ΔU\mathrm{Q}=\Delta \mathrm{U}
E) Q=0\mathrm{Q}=0
سؤال
A friend tells you that he knows of a situation in which heat is passed from one body to another body with a higher temperature. He explains that he thinks the 2nd law of thermodynamics must have been violated. Is he correct?

A) No. The cooler body can give up energy to the hotter body by radioactivity or another natural process.
B) No. If the temperature difference is small enough, heat can spontaneously flow from the cooler to the hotter body.
C) Yes. Heat cannot pass from a cooler body to a hotter body.
D) No. He forgot that if external work is done on the system this is possible.
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Deck 15: Thermodynamics
1
On a PV\mathrm{PV} diagram where pressure is in atmospheres and V\mathrm{V} is in liters the area is measured in liter-atmospheres. What is the number of Joules in 1.00 liter-atmosphere?

A) 101.3
B) 15.7
C) 65.2
D) 83.1
E) 22.4
101.3
2
Using 0.0200 mol0.0200 \mathrm{~mol} of an ideal monatomic gas, an isochoric process from state A(230kPa,1.0 L\mathrm{A}(230 \mathrm{kPa}, 1.0 \mathrm{~L} ) to B(98\mathrm{B}(98 kPa,1.0 L\mathrm{kPa}, 1.0 \mathrm{~L} ) results in what change in internal energy?

A) 375 J-375 \mathrm{~J}
B) 200 J-200 \mathrm{~J}
C) +200 J+200 \mathrm{~J}
D) +375 J+375 \mathrm{~J}
200 J-200 \mathrm{~J}
3

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at a constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . How much heat is absorbed by the gas?

A) 288 J288 \mathrm{~J}
B) 389 J389 \mathrm{~J}
C) 544 J544 \mathrm{~J}
D) 436 J436 \mathrm{~J}

436 J436 \mathrm{~J}
4

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . What is the change of volume of the gas in this process?

A) 0.86 L0.86 \mathrm{~L}
B) 1.88 L1.88 \mathrm{~L}
C) 2.09 L2.09 \mathrm{~L}
D) 1.23 L1.23 \mathrm{~L}

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5

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . What is the work done by the gas during this expansion?

A) 172 J172 \mathrm{~J}
B) 125 J125 \mathrm{~J}
C) 159 J159 \mathrm{~J}
D) 102 J102 \mathrm{~J}

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6

1.00 mol1.00 \mathrm{~mol} of oxygen gas (O2)\left(\mathrm{O}_{2}\right) is heated at constant pressure of 1.00 atm1.00 \mathrm{~atm} from 10.0C10.0^{\circ} \mathrm{C} to 25.0C25.0^{\circ} \mathrm{C} . From the first law, calculate the change of internal energy of the gas in this process.

A) 365 J365 \mathrm{~J}
B) 155 J155 \mathrm{~J}
C) 291 J291 \mathrm{~J}
D) 312 J312 \mathrm{~J}

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7
A very efficient engine has the following characteristics-combustion =1,900C=1,900^{\circ} \mathrm{C} , exhaust =430C,5.0×=430^{\circ} \mathrm{C}, 5.0 \times 10610^{6} cal of fuel produces 1.4×107 J1.4 \times 10^{7} \mathrm{~J} of work in one hour. What is the output in hp\mathrm{hp} ? (1hp=745.7 W)(1 \mathrm{hp}=745.7 \mathrm{~W})

A) 7.3hp7.3 \mathrm{hp}
B) 5.2hp5.2 \mathrm{hp}
C) 8.1hp8.1 \mathrm{hp}
D) 6.3hp6.3 \mathrm{hp}
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8
A heat engine has an efficiency of 25.0%25.0 \% and a power output of 600 W600 \mathrm{~W} . What is the rate of heat input?

A) 2.4 kW2.4 \mathrm{~kW} .
B) 1.8 kW1.8 \mathrm{~kW} .
C) 3.0 kW3.0 \mathrm{~kW} .
D) 2.0 kW2.0 \mathrm{~kW} .
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9
A refrigerator uses 40.0 J40.0 \mathrm{~J} of work to extract 90.0 J90.0 \mathrm{~J} from a heat reservoir at 0.00C0.00^{\circ} \mathrm{C} . What is the coefficient of performance for the refrigerator?

A) 2.05
B) 2.85
C) 2.25
D) 1.60
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10
120 J120 \mathrm{~J} of heat flows by thermal conduction from 100C100^{\circ} \mathrm{C} to 0.00C0.00^{\circ} \mathrm{C} . What is the net change in entropy for this process?

A) 0.034 J/K0.034 \mathrm{~J} / \mathrm{K}
B) 0.118 J/K0.118 \mathrm{~J} / \mathrm{K}
C) 0.338 J/K0.338 \mathrm{~J} / \mathrm{K}
D) 0.201 J/K0.201 \mathrm{~J} / \mathrm{K}

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11

When 1.000 kg1.000 \mathrm{~kg} of ice melts, 33.00×104 J/kg33.00 \times 10^{4} \mathrm{~J} / \mathrm{kg} of heat are needed. What is the entropy change of the ice in the melting process?

A) 1,684 J/K1,684 \mathrm{~J} / \mathrm{K}
B) 1,209 J/K1,209 \mathrm{~J} / \mathrm{K}
C) 758.0 J/K758.0 \mathrm{~J} / \mathrm{K}
D) 2,316 J/K2,316 \mathrm{~J} / \mathrm{K}

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12
When 2.000 kg2.000 \mathrm{~kg} of water evaporates, 22.60×105 J/kg22.60 \times 10^{5} \mathrm{~J} / \mathrm{kg} of heat are needed. What is the entropy change of the water in the boiling process?

A) 6,750 J/K6,750 \mathrm{~J} / \mathrm{K}
B) 12,120 J/K12,120 \mathrm{~J} / \mathrm{K}
C) 5,844 J/K5,844 \mathrm{~J} / \mathrm{K}
D) 8,566 J/K8,566 \mathrm{~J} / \mathrm{K}
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13
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(\mathrm{T}_{\mathrm{F}} / \mathrm{T}_{\mathrm{i}}\right) , where m\mathrm{m} is the mass of the sample, c\mathrm{c} is the specific heat of the sample, and TF\mathrm{T}_{\mathrm{F}} and Ti\mathrm{T}_{\mathrm{i}} are the final and initial temperatures, respectively. What is the change in entropy when 10.0 grams of lead with a specific heat of 0.452 J/gK0.452 \mathrm{~J} / \mathrm{g} \mathrm{K} is heated from 10.0C10.0^{\circ} \mathrm{C} to 50.0C50.0^{\circ} \mathrm{C} ?

A) 0.90 J/K0.90 \mathrm{~J} / \mathrm{K}
B) 0.30 J/K0.30 \mathrm{~J} / \mathrm{K}
C) 0.60 J/K0.60 \mathrm{~J} / \mathrm{K}
D) 0.45 J/K0.45 \mathrm{~J} / \mathrm{K}
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14
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(\mathrm{T}_{\mathrm{F}} / \mathrm{T}_{\mathrm{i}}\right) , where m\mathrm{m} is the mass of the sample, c\mathrm{c} is the specific heat of the sample, and TF\mathrm{T}_{\mathrm{F}} and Ti\mathrm{T}_{\mathrm{i}} are the final and initial temperatures, respectively. What is the change in entropy when 20.0 grams of aluminum with a specific heat of 0.900 J/gK0.900 \mathrm{~J} / \mathrm{g} \mathrm{K} is cooled from 60.0C60.0^{\circ} \mathrm{C} to 10.0C10.0^{\circ} \mathrm{C} ?

A) +2.93 J/K+2.93 \mathrm{~J} / \mathrm{K}
B) 0.00 J/K0.00 \mathrm{~J} / \mathrm{K}
C) +2.50 J/K+2.50 \mathrm{~J} / \mathrm{K}
D) 2.93 J/K-2.93 \mathrm{~J} / \mathrm{K}
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15
It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS=mcln\Delta \mathrm{S}=\mathrm{mc} \ln (TF/Ti)\left(T_{F} / T_{i}\right) , where mm is the mass of the sample, cc is the specific heat of the sample, and TFT_{F} and TiT_{i} are the final and initial temperatures, respectively. What is the change in entropy when 20.0 grams of aluminum with a specific heat of 0.900 J/gK0.900 \mathrm{~J} / \mathrm{g} \mathrm{K} is heated from 10.0C10.0^{\circ} \mathrm{C} to 60.0C60.0^{\circ} \mathrm{C} ?

A) 2.93 J/K-2.93 \mathrm{~J} / \mathrm{K}
B) +2.50 J/K+2.50 \mathrm{~J} / \mathrm{K}
C) +2.93 J/K+2.93 \mathrm{~J} / \mathrm{K}
D) 0 J/K0 \mathrm{~J} / \mathrm{K}
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16
2.00 moles of an ideal gas freely expands from 1.50 liters to 4.00 liters. The change in entropy in the expansion is

A) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
B) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
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17
1.50 moles of an ideal gas freely expands from 1.00 liter to 4.50 liters. The change in entropy of the gas in the expansion is

A) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
B) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
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18
One mole of an ideal gas freely expands from 1.00 liter to 2.00 liters. The change in entropy of the gas in the expansion is

A) 5.80 J/K5.80 \mathrm{~J} / \mathrm{K}
B) 8.50 J/K8.50 \mathrm{~J} / \mathrm{K}
C) 18.7 J/K18.7 \mathrm{~J} / \mathrm{K}
D) 16.3 J/K16.3 \mathrm{~J} / \mathrm{K}
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19
A system in a certain macrostate has 1.2×1031.2 \times 10^{3} microstates. Through some process, the system changes the number of microstates to 3×1043 \times 10^{4} . What is the change in entropy for the process?

A) 1.1×1023 J/K1.1 \times 10^{-23} \mathrm{~J} / \mathrm{K}
B) 4.4×1023 J/K4.4 \times 10^{-23} \mathrm{~J} / \mathrm{K}
C) 5.6×1023 J/K5.6 \times 10^{-23} \mathrm{~J} / \mathrm{K}
D) 2.1×1023 J/K2.1 \times 10^{-23} \mathrm{~J} / \mathrm{K}
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20
On a PV diagram, what kind of process is represented by a horizontal line with an arrow left to right?

A) Isobaric compression
B) Isothermal compression
C) Adiabatic process
D) Isothermal expansion
E) Isobaric expansion
F) Isochoric process
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21
On a PV diagram, what kind of process is represented by a vertical line with an arrow pointing downward?

A) Isobaric compression
B) Isothermal expansion
C) Isothermal compression
D) Adiabatic process
E) Isochoric process
F) Isobaric expansion
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22
For a system undergoing an adiabatic process,

A) Q=ΔUQ=\Delta U
B) Q=W\mathrm{Q}=-\mathrm{W}
C) Q=ΔU\mathrm{Q}=-\Delta \mathrm{U}
D) Q=W\mathrm{Q}=\mathrm{W}
E) Q=0\mathrm{Q}=0
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23
For a system undergoing an isothermal process,

A) Q=W\mathrm{Q}=-\mathrm{W}
B) Q=ΔU\mathrm{Q}=-\Delta \mathrm{U}
C) Q=W\mathrm{Q}=\mathrm{W}
D) Q=ΔU\mathrm{Q}=\Delta \mathrm{U}
E) Q=0\mathrm{Q}=0
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24
A friend tells you that he knows of a situation in which heat is passed from one body to another body with a higher temperature. He explains that he thinks the 2nd law of thermodynamics must have been violated. Is he correct?

A) No. The cooler body can give up energy to the hotter body by radioactivity or another natural process.
B) No. If the temperature difference is small enough, heat can spontaneously flow from the cooler to the hotter body.
C) Yes. Heat cannot pass from a cooler body to a hotter body.
D) No. He forgot that if external work is done on the system this is possible.
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