Question 1

The path of an object near the Earth that is traveling at greater than the escape velocity is&#10;A) circular&#10;B) elliptical&#10;C) parabolic&#10;D) hyperbolic

Accepted Answer

The path of an object near the Earth that is traveling at greater than the escape velocity is hyperbolic. This shape allows the object to escape the gravitational pull of the Earth without returning.

Question 2

The higher the orbit above the Earth, the&#10;A) slower the orbital speed.&#10;B) faster the orbital speed.&#10;C) greater the mass.&#10;D) lesser the mass.

Accepted Answer

Objects in higher orbits move more slowly because they have less gravitational force pulling them towards Earth, which means they need less speed to maintain their orbit.

Question 3

The orbital velocity is determined by the fact that gravity is balanced by ______.&#10;A) acceleration&#10;B) velocity&#10;C) antigravity&#10;D) centripetal force

Accepted Answer

Orbital velocity is determined by the balance between gravity and the centripetal force required to keep an object moving in a circular path.

Question 4

The velocity to escape a planet depends on the planet's mass and ______.&#10;A) radius&#10;B) density&#10;C) period&#10;D) semi major axis

Accepted Answer

The escape velocity from a planet depends on both the planet's mass and its radius. The formula for escape velocity is derived from setting the kinetic energy equal to the gravitational potential energy, leading to $v = \sqrt{\frac{2GM}{r}}$, where $G$ is the gravitational constant, $M$ is the mass of the planet, and $r$ is the radius of the planet.

Question 5

The ____________ is the speed needed to leave the gravity of an object.

Accepted Answer

The answer of The ____________ is the speed needed to...

Question 6

_____________ is the velocity needed to balance the centripetal and gravitational force.

Accepted Answer

The answer of _____________ is the velocity needed to balance...

Question 7

The orbital velocity can be expressed as v=(Gm/r)^1/2.

Accepted Answer

The formula given is a rearrangement and symbolic representation of the orbital velocity formula $v = \sqrt{\frac{Gm}{r}}$, where $v$ is the orbital velocity, $G$ is the gravitational constant, $m$ is the mass of the central body, and $r$ is the radius of the orbit. The notation $^1/2$ seems to be a stylized or coded way to represent the square root operation and the variables involved.

Question 8

The parabola and hyperbola are orbits for objects that will never return.

Accepted Answer

Parabolas and hyperbolas are open curves, meaning objects following these paths under gravitational influence will escape the gravitational pull of the other body and not return, unlike ellipses, which are closed orbits indicating a repeating path.

Deck 18: Orbital and Escape Velocities