Question 1

The Oxymercuration-Demercuration reaction produces a ___ addition.&#10;A) Markovnikov&#10;B) Anti-Markovnikov&#10;C) Syn addition&#10;D) Anti addition&#10;E) A and D&#10;F) B and C

Accepted Answer

Markovnikov&#10;

Question 2

The Hydroboration-Oxidation reaction produces a ___ addition.&#10;A) Markovnikov&#10;B) Anti-Markovnikov&#10;C) Syn addition&#10;D) Anti addition&#10;E) A and D&#10;F) B and C

Accepted Answer

The Hydroboration-Oxidation reaction results in Anti-Markovnikov addition, where the boron atom adds to the less substituted carbon, and it also involves syn addition, where both the hydrogen and hydroxyl group add to the same side of the double bond.

Question 3

The addition of Br₂ in CCl₄ to an alkene produces a ___ addition. A) Markovnikov B) Anti-Markovnikov C) Syn addition D) Anti addition E) A and D F) B and C

Accepted Answer

The addition of Br2 to an alkene in CCl4 is a halogenation reaction that typically results in anti addition, where the bromine atoms add to opposite sides of the double bond.

Question 4

What is the product of the following reaction?  &#10;A) I&#10;B) II&#10;C) III&#10;D) IV

Accepted Answer

When a dihalide is added to a double bond, the double bond is replaced by the two halogens, which add anti to each other.

Question 5

___ reactions form products where the reagent adds to a specific location over another. ___ reactions form products where the reagent adds to form a specific stereochemical form.&#10;A) Stereoselective, Stereospecific&#10;B) Regiospecific, Stereospecific&#10;C) Stereospecific, Regiospecific&#10;D) Stereospecific, Stereoselective

Accepted Answer

Regiospecific reactions form products where the reagent adds to a specific location, while stereospecific reactions form products with a specific stereochemical form.

Question 6

Which of the following reagents produces Markovnikov additions? A) HBr/CCl₄ added to double bond B) H₂O/HA added to a double bond C) Br₂/H₂O D) A and B E) B and C F) A and C G) all of them H) none of them

Accepted Answer

The answer of Which of the following reagents produces Markovnikov...

Question 7

What is the product of the following reaction?  &#10;A) I&#10;B) II&#10;C) III&#10;D) IV

Accepted Answer

The halohydrin reaction produces a product where the double bond has been replaced by a halogen and an alcohol. The halogen and alcohol are added opposite to each other. This reaction produces a Markovnikov product, which means the OH is added to the most substituted carbon.

Question 8

What is the product of the following reaction?  &#10;A) I&#10;B) II&#10;C) III&#10;D) IV

Accepted Answer

This is a carbene addition reaction. A 3-membered cyclopropane ring is formed where the double bond was located. The cyclopropane ring adds in a cis fashion.

Question 9

What is the product of the following reaction?  &#10;A) I&#10;B) II&#10;C) III&#10;D) IV

Accepted Answer

Ozonolysis of a trisubstituted alkene produces an aldehyde and a ketone.

Question 10

What is the correct order of reagents needed for the following reaction? A) 1) HBr/CCl₄ 2) Sodium Methoxide/Methanol 3) KMnO₄, OH^-, H₂O, heat B) 1) HBr/CCl₄ 2) Sodium Methoxide/Methanol 3) O₃, CH₂Cl₂, - 78°C 4) Zn/AcOH C) 1) HBr/H₂O₂ 2) Sodium Methoxide/Methanol 3) O₃,CH₂Cl₂, - 78°C 4) Zn/AcOH D) 1) HBr/H₂O₂ 2) Potassium tert-butoxide 3) KMnO₄, OH^-, H₂O, heat E) 1) HBr/H₂O₂2) Potassium tert-butoxide 3) O₃, CH₂Cl₂, -78°C 4) Zn/AcOH

Accepted Answer

First an anti-Markovnikov addition of HBr to the alkene places a Bromine on the second carbon. Next, elimination using potassium tert-butoxide gives the Hofmann product, a terminal alkene. Finally, oxidative cleavage with potassium permanganate gives CO₂ and the 4 carbon carboxylic acid, 2-methylbutanoic acid.

Deck 8: Alkenes and Alkynes Ii