Deck 17: Nonparametric Methods: Goodness-Of-Fit Tests

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سؤال
The chi-square distribution is positively skewed.
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سؤال
A Chi-square goodness-of-fit test is used to determine how well an observed distribution fits an __________ distribution.
سؤال
The chi-square test statistic used in a goodness-of-fit test has k-1 degrees of freedom.
سؤال
Nonparametric tests require no assumptions about the shape of the population distribution.
سؤال
The computed value of chi-square statistic is always positive because the numerator is the difference between the observed frequencies and the expected frequencies _______________.
سؤال
A scatter plot is a useful graphical method to determine if a set of sample data is from a normal population.
سؤال
The claim that "male and female students at Coastal Carolina University prefer different parking lots on campus" is an example of a chi-square null hypothesis.
سؤال
The shape of the chi-square distribution changes for each number of degrees of freedom.
سؤال
There is not one, but a family of chi-square distributions. There is a chi-square distribution for 1 degree of freedom, another for 2 degrees of freedom, another for 3 degrees of freedom, and so on.
سؤال
To test the null hypothesis that a set of sample data is normally distributed, we compare an expected normal distribution of the data to an observed distribution of the data.
سؤال
What is the null hypothesis in the goodness-of-fit test? ____________
سؤال
The shape of the chi-square distribution depends on the size of the sample.
سؤال
A t-statistic is useful for computing an expected normal distribution.
سؤال
What is the lowest level of data for which the chi-square goodness-of-fit test is appropriate? ______________
سؤال
As the degrees of freedom increase, the shape of a chi-square distribution approaches a ______________________ distribution.
سؤال
A F-test is useful for testing the null hypothesis that a set of sample data is normally distributed.
سؤال
For a contingency table, the expected frequency for a cell is found by dividing the row total by the grand total.
سؤال
In the goodness-of-fit test, the chi-square distribution is used to determine how well an observed distribution of observations "fits" an expected distribution of observations.
سؤال
For a goodness-of-fit test, the following are possible null and alternate hypotheses:
H0: Sales are uniformly distributed among the five locations.
H1: Sales are not uniformly distributed among the five locations.
سؤال
For the goodness-of-fit test, the use of the chi-square statistic would be permissible in the following problem. For the goodness-of-fit test, the use of the chi-square statistic would be permissible in the following problem.  <div style=padding-top: 35px>
سؤال
A contingency table shows the frequencies for three levels of income with gender. What are the degrees of freedom to test the null hypothesis that income and gender are independent? ______
سؤال
If the computed value of a chi-square statistic is greater than the critical value, what is the decision regarding the null hypothesis? _________
سؤال
In a contingency table, the decision to reject the null hypothesis is based on a __________ test statistic.
سؤال
To verify that a frequency distribution for sample data is normally distributed, the expected frequencies are computed using probabilities from a _____________ distribution.
سؤال
To test a hypothesis that a frequency distribution for sample data is normally distributed, class limits are transformed using a _____________.
سؤال
For contingency table test of independence, the formula to compute the degrees of freedom is ___________________________________
سؤال
What is the shape of the chi-square distribution? ___________________
سؤال
The Anderson-Darling tests a null hypothesis that the sample data are _____________ distributed.
سؤال
To test a hypothesis to verify that a frequency distribution for sample data is normally distributed, the expected frequencies are _______________ distributed.
سؤال
For any goodness-of-fit test, the null hypothesis is that there is ____ difference between the expected and observed distributions.
سؤال
When testing a goodness-of-fit null hypothesis, and there are extremely large differences between observed and expected frequencies, what decision should be made? ____________
سؤال
Contingency table analysis can be used to test for a relationship between two _________ scaled variables.
سؤال
The Anderson-Darling test compares a cumulative normal distribution to a cumulative distribution of the ___________ data.
سؤال
In a contingency table, the decision to reject the null hypothesis is based on a __________ test statistic.
سؤال
If the significance level for an Anderson-Darling test is 0.05 and the p-value is 0.001, the null hypothesis is rejected and we conclude that the data _________ normally distributed.
سؤال
The test statistic for a goodness-of-fit test for unequal expected frequencies is a __________ statistic.
سؤال
In a contingency table, multiplying the row total by the column total and dividing by the ___________ computes the expected frequency for a cell.
سؤال
To verify that a frequency distribution for sample data is normally distributed, a _____________ statistic is used to test the hypothesis that the sample data is normally distributed.
سؤال
For hypothesis tests using a chi-square statistic, the rejection region is in the _____________ tail of the chi-square distribution.
سؤال
What is the degree of freedom for a chi-square goodness-of-fit test? ____________________________
سؤال
A sample of 100 production workers is obtained. The workers are classified by gender (male, female) and by age (under 20, 20-29, 30-39 and 40 or over). How many degrees of freedom are there?

A) 0
B) 3
C) 6
D) 5
سؤال
Which of the following are correct statements regarding the goodness-of-fit test?

A) Data may be of nominal scale
B) Population must be normal
C) All the expected frequencies must be equal
D) All the expected frequencies must be unequal
سؤال
A question has these possible choices-excellent, very good, good, fair and unsatisfactory. How many degrees of freedom are there using the goodness-of-fit test to the sample results?

A) 0
B) 2
C) 4
D) 5
سؤال
The following table classifies an individual in two ways-by gender and by college attended. <strong>The following table classifies an individual in two ways-by gender and by college attended.   What is this two-way classification called?</strong> A) Goodness-of-fit test B) Frequency table C) ANOVA table D) Contingency table <div style=padding-top: 35px> What is this two-way classification called?

A) Goodness-of-fit test
B) Frequency table
C) ANOVA table
D) Contingency table
سؤال
What is the decision regarding the differences between the observed and expected frequencies if the critical value of chi-square is 9.488 and the computed value is 6.079?

A) The difference is probably due to sampling error; do not reject the null hypothesis
B) Not due to chance; reject the null hypothesis
C) Not due to chance; do not reject the alternate hypothesis
D) Too close; reserve judgment
سؤال
To analyze data cross-classified in a contingency table, how are the degrees of freedom computed?

A) N - 1
B) Rows - Columns
C) (Rows) x (Columns)
D) (Rows - 1) x (Columns - 1)
سؤال
The educational level and the social activity of a sample of executives follow. <strong>The educational level and the social activity of a sample of executives follow.   What does the expected frequency for the above average social activity and high school education equal?</strong> A) 9.50 B) 60.00 C) 22.50 D) 28.50 <div style=padding-top: 35px> What does the expected frequency for the "above average" social activity and "high school" education equal?

A) 9.50
B) 60.00
C) 22.50
D) 28.50
سؤال
The chi-square statistic

A) is greater than or equal to zero.
B) is less than or equal to zero.
C) can be any value.
D) is equal to zero.
سؤال
What is our decision for a goodness-of-fit test with a computed value of chi-square of 1.273 and a critical value of 13.388?

A) Do not reject the null hypothesis
B) Reject the null hypothesis
C) Unable to reject or not reject the null hypothesis based on data
D) Should take a larger sample
سؤال
Three new colors have been proposed for the Jeep Grand Cherokee vehicle. They are silvered-blue, almond, and willow green. The null hypothesis for a goodness-of-fit test would be

A) willow green is preferred over the other colors.
B) that there is no preference between the colors.
C) any one color is preferred over the other colors.
D) impossible to determine.
سؤال
The chi-square statistic has

A) one distribution.
B) two distributions.
C) a family of distributions.
D) a uniform distribution.
سؤال
Which of the following are correct statements regarding the chi-square distribution?

A) Distribution is negatively skewed.
B) Chi-square is based on two sets of degrees of freedom, one for the numerator and one for the denominator.
C) Its shape is based on the degrees of freedom.
D) The variance is equal to one.
سؤال
The chi-square distribution becomes more symmetrical as

A) number of variables increase.
B) the chi-square value increases.
C) degrees of freedom decrease.
D) degrees of freedom increase.
سؤال
Which of the following assumptions is necessary to apply a goodness-of-fit test?

A) Normal population is required.
B) The data are measured with a nominal or ordinal scale.
C) Population variance must be known.
D) Both "a" and "c".
سؤال
The chi-square distribution is

A) positively skewed.
B) negatively skewed.
C) normally distributed.
D) negatively or positively skewed.
سؤال
What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?

A) 3.841
B) 5.991
C) 7.815
D) 11.070
سؤال
For any chi-square goodness-of-fit problem, the number of degrees of freedom is found by

A) n - k - 1.
B) k - 1.
C) n + 1.
D) n + k.
سؤال
A distributor of personal computers has five locations in the city. The sales in units for the first quarter of the year were as follows: <strong>A distributor of personal computers has five locations in the city. The sales in units for the first quarter of the year were as follows:   What is the critical value at the 0.01 level of risk?</strong> A) 7.779 B) 15.033 C) 13.277 D) 5.412 <div style=padding-top: 35px> What is the critical value at the 0.01 level of risk?

A) 7.779
B) 15.033
C) 13.277
D) 5.412
سؤال
For people released from prison, the following table shows their adjustment to civilian life and place of residence. <strong>For people released from prison, the following table shows their adjustment to civilian life and place of residence.   What is the critical value for this contingency table at the 0.01 level of significance?</strong> A) 9.488 B) 2.070 C) 11.345 D) 13.277 <div style=padding-top: 35px> What is the critical value for this contingency table at the 0.01 level of significance?

A) 9.488
B) 2.070
C) 11.345
D) 13.277
سؤال
Two chi-square distributions were plotted on the same chart. One distribution was for 3 degrees of freedom and the other was for 12 degrees of freedom. Which distribution would tend to approach a normal distribution?

A) 3 degrees
B) 12 degrees
C) 15 degrees
D) All would
سؤال
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the expected frequency?</strong> A) 9 B) 10 C) 11 D) 12 <div style=padding-top: 35px> What is the expected frequency?

A) 9
B) 10
C) 11
D) 12
سؤال
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What kind of frequencies are the numbers 12, 9, 11, 10, 9, and 9 called?</strong> A) Acceptance B) Critical value C) Expected D) Observed <div style=padding-top: 35px> What kind of frequencies are the numbers 12, 9, 11, 10, 9, and 9 called?

A) Acceptance
B) Critical value
C) Expected
D) Observed
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   Using 0.05 as the significance level, what is the critical value for the test statistic?</strong> A) 9.488 B) 5.991 C) 7.815 D) 3.841 <div style=padding-top: 35px> Using 0.05 as the significance level, what is the critical value for the test statistic?

A) 9.488
B) 5.991
C) 7.815
D) 3.841
سؤال
For a chi-square test involving a contingency table, suppose the null hypothesis is rejected. We conclude that the two variables are

A) linear.
B) curvilinear.
C) not related.
D) related.
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   Based on the analysis, what can be concluded?</strong> A) Social activity and education are correlated. B) Social activity and education are not related. C) Social activity and education are related. D) No conclusion is possible. <div style=padding-top: 35px> Based on the analysis, what can be concluded?

A) Social activity and education are correlated.
B) Social activity and education are not related.
C) Social activity and education are related.
D) No conclusion is possible.
سؤال
The computed chi-square value is positive because the difference between the observed and expected frequencies is

A) squared.
B) linear.
C) uniform.
D) always positive.
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The appropriate test statistic for the analysis is a:</strong> A) F-statistic B) T-statistic C) Chi-square statistic D) Z-statistic <div style=padding-top: 35px> The appropriate test statistic for the analysis is a:

A) F-statistic
B) T-statistic
C) Chi-square statistic
D) Z-statistic
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The null hypothesis for the analysis is:</strong> A) There is no relationship between social activity and education. B) The correlation between social activity and education is zero. C) As social activity increases, education increases. D) The mean of social activity equals the mean of education. <div style=padding-top: 35px> The null hypothesis for the analysis is:

A) There is no relationship between social activity and education.
B) The correlation between social activity and education is zero.
C) As social activity increases, education increases.
D) The mean of social activity equals the mean of education.
سؤال
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   How many degrees of freedom are there?</strong> A) 0 B) 3 C) 4 D) 5 <div style=padding-top: 35px> How many degrees of freedom are there?

A) 0
B) 3
C) 4
D) 5
سؤال
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   The null hypothesis for the analysis is:</strong> A) There is no relationship between gender and driving behavior. B) The correlation between driving behavior and gender is zero. C) As driving behavior increases, gender increases. D) The mean of driving behavior equals the mean of gender. <div style=padding-top: 35px> The null hypothesis for the analysis is:

A) There is no relationship between gender and driving behavior.
B) The correlation between driving behavior and gender is zero.
C) As driving behavior increases, gender increases.
D) The mean of driving behavior equals the mean of gender.
سؤال
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the calculated value of chi-square?</strong> A) 1.0 B) 0.5 C) 0.8 D) 8.0 <div style=padding-top: 35px> What is the calculated value of chi-square?

A) 1.0
B) 0.5
C) 0.8
D) 8.0
سؤال
Which of the following can be used to test the hypothesis that two nominal variables are related?

A) a contingency table.
B) a chi-square table.
C) an ANOVA table.
D) a scatter diagram.
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The appropriate test to analyze the relationship between social activity and education is:</strong> A) Regression analysis B) Analysis of variance C) Contingency table analysis D) Goodness-of-fit <div style=padding-top: 35px> The appropriate test to analyze the relationship between social activity and education is:

A) Regression analysis
B) Analysis of variance
C) Contingency table analysis
D) Goodness-of-fit
سؤال
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:  <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the critical value of chi-square with  \alpha  = 0.05?</strong> A) 11.070 B) 12.592 C) 13.388 D) 15.033 <div style=padding-top: 35px>
What is the critical value of chi-square with α\alpha = 0.05?

A) 11.070
B) 12.592
C) 13.388
D) 15.033
سؤال
When determining how well an observed set of frequencies fit an expected set of frequencies, what is the test statistic?

A) F-statistic.
B) t-statistic.
C) <strong>When determining how well an observed set of frequencies fit an expected set of frequencies, what is the test statistic?</strong> A) F-statistic. B) t-statistic. C)   statistic. D) z-statistic. <div style=padding-top: 35px> statistic.
D) z-statistic.
سؤال
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   The degrees of freedom for the analysis is:</strong> A) 1 B) 2 C) 3 D) 4 <div style=padding-top: 35px> The degrees of freedom for the analysis is:

A) 1
B) 2
C) 3
D) 4
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The degrees of freedom for the analysis is:</strong> A) 1 B) 2 C) 3 D) 4 <div style=padding-top: 35px> The degrees of freedom for the analysis is:

A) 1
B) 2
C) 3
D) 4
سؤال
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   What is the value of the test statistic?</strong> A) 100 B) 83.67 C) 50 D) 4.94 <div style=padding-top: 35px> What is the value of the test statistic?

A) 100
B) 83.67
C) 50
D) 4.94
سؤال
In a goodness-of-fit test, the null hypothesis (no difference between sets of observed and expected frequencies) is rejected when the

A) computed chi-square is less than the critical value.
B) difference between the observed and expected frequencies is significantly large.
C) difference between the observed and expected frequencies is small.
D) difference between the observed and expected frequencies occurs by chance.
سؤال
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   Using 0.05 as the significance level, what is the critical value for the test statistic?</strong> A) 9.488 B) 5.991 C) 7.815 D) 3.841 <div style=padding-top: 35px> Using 0.05 as the significance level, what is the critical value for the test statistic?

A) 9.488
B) 5.991
C) 7.815
D) 3.841
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Deck 17: Nonparametric Methods: Goodness-Of-Fit Tests
1
The chi-square distribution is positively skewed.
True
2
A Chi-square goodness-of-fit test is used to determine how well an observed distribution fits an __________ distribution.
Expected
3
The chi-square test statistic used in a goodness-of-fit test has k-1 degrees of freedom.
True
4
Nonparametric tests require no assumptions about the shape of the population distribution.
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The computed value of chi-square statistic is always positive because the numerator is the difference between the observed frequencies and the expected frequencies _______________.
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6
A scatter plot is a useful graphical method to determine if a set of sample data is from a normal population.
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7
The claim that "male and female students at Coastal Carolina University prefer different parking lots on campus" is an example of a chi-square null hypothesis.
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8
The shape of the chi-square distribution changes for each number of degrees of freedom.
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9
There is not one, but a family of chi-square distributions. There is a chi-square distribution for 1 degree of freedom, another for 2 degrees of freedom, another for 3 degrees of freedom, and so on.
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10
To test the null hypothesis that a set of sample data is normally distributed, we compare an expected normal distribution of the data to an observed distribution of the data.
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11
What is the null hypothesis in the goodness-of-fit test? ____________
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12
The shape of the chi-square distribution depends on the size of the sample.
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13
A t-statistic is useful for computing an expected normal distribution.
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14
What is the lowest level of data for which the chi-square goodness-of-fit test is appropriate? ______________
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15
As the degrees of freedom increase, the shape of a chi-square distribution approaches a ______________________ distribution.
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16
A F-test is useful for testing the null hypothesis that a set of sample data is normally distributed.
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17
For a contingency table, the expected frequency for a cell is found by dividing the row total by the grand total.
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18
In the goodness-of-fit test, the chi-square distribution is used to determine how well an observed distribution of observations "fits" an expected distribution of observations.
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19
For a goodness-of-fit test, the following are possible null and alternate hypotheses:
H0: Sales are uniformly distributed among the five locations.
H1: Sales are not uniformly distributed among the five locations.
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20
For the goodness-of-fit test, the use of the chi-square statistic would be permissible in the following problem. For the goodness-of-fit test, the use of the chi-square statistic would be permissible in the following problem.
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21
A contingency table shows the frequencies for three levels of income with gender. What are the degrees of freedom to test the null hypothesis that income and gender are independent? ______
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22
If the computed value of a chi-square statistic is greater than the critical value, what is the decision regarding the null hypothesis? _________
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23
In a contingency table, the decision to reject the null hypothesis is based on a __________ test statistic.
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24
To verify that a frequency distribution for sample data is normally distributed, the expected frequencies are computed using probabilities from a _____________ distribution.
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25
To test a hypothesis that a frequency distribution for sample data is normally distributed, class limits are transformed using a _____________.
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26
For contingency table test of independence, the formula to compute the degrees of freedom is ___________________________________
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27
What is the shape of the chi-square distribution? ___________________
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28
The Anderson-Darling tests a null hypothesis that the sample data are _____________ distributed.
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29
To test a hypothesis to verify that a frequency distribution for sample data is normally distributed, the expected frequencies are _______________ distributed.
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30
For any goodness-of-fit test, the null hypothesis is that there is ____ difference between the expected and observed distributions.
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31
When testing a goodness-of-fit null hypothesis, and there are extremely large differences between observed and expected frequencies, what decision should be made? ____________
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32
Contingency table analysis can be used to test for a relationship between two _________ scaled variables.
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33
The Anderson-Darling test compares a cumulative normal distribution to a cumulative distribution of the ___________ data.
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34
In a contingency table, the decision to reject the null hypothesis is based on a __________ test statistic.
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35
If the significance level for an Anderson-Darling test is 0.05 and the p-value is 0.001, the null hypothesis is rejected and we conclude that the data _________ normally distributed.
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36
The test statistic for a goodness-of-fit test for unequal expected frequencies is a __________ statistic.
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37
In a contingency table, multiplying the row total by the column total and dividing by the ___________ computes the expected frequency for a cell.
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38
To verify that a frequency distribution for sample data is normally distributed, a _____________ statistic is used to test the hypothesis that the sample data is normally distributed.
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39
For hypothesis tests using a chi-square statistic, the rejection region is in the _____________ tail of the chi-square distribution.
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40
What is the degree of freedom for a chi-square goodness-of-fit test? ____________________________
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41
A sample of 100 production workers is obtained. The workers are classified by gender (male, female) and by age (under 20, 20-29, 30-39 and 40 or over). How many degrees of freedom are there?

A) 0
B) 3
C) 6
D) 5
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42
Which of the following are correct statements regarding the goodness-of-fit test?

A) Data may be of nominal scale
B) Population must be normal
C) All the expected frequencies must be equal
D) All the expected frequencies must be unequal
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43
A question has these possible choices-excellent, very good, good, fair and unsatisfactory. How many degrees of freedom are there using the goodness-of-fit test to the sample results?

A) 0
B) 2
C) 4
D) 5
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44
The following table classifies an individual in two ways-by gender and by college attended. <strong>The following table classifies an individual in two ways-by gender and by college attended.   What is this two-way classification called?</strong> A) Goodness-of-fit test B) Frequency table C) ANOVA table D) Contingency table What is this two-way classification called?

A) Goodness-of-fit test
B) Frequency table
C) ANOVA table
D) Contingency table
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45
What is the decision regarding the differences between the observed and expected frequencies if the critical value of chi-square is 9.488 and the computed value is 6.079?

A) The difference is probably due to sampling error; do not reject the null hypothesis
B) Not due to chance; reject the null hypothesis
C) Not due to chance; do not reject the alternate hypothesis
D) Too close; reserve judgment
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46
To analyze data cross-classified in a contingency table, how are the degrees of freedom computed?

A) N - 1
B) Rows - Columns
C) (Rows) x (Columns)
D) (Rows - 1) x (Columns - 1)
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47
The educational level and the social activity of a sample of executives follow. <strong>The educational level and the social activity of a sample of executives follow.   What does the expected frequency for the above average social activity and high school education equal?</strong> A) 9.50 B) 60.00 C) 22.50 D) 28.50 What does the expected frequency for the "above average" social activity and "high school" education equal?

A) 9.50
B) 60.00
C) 22.50
D) 28.50
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48
The chi-square statistic

A) is greater than or equal to zero.
B) is less than or equal to zero.
C) can be any value.
D) is equal to zero.
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49
What is our decision for a goodness-of-fit test with a computed value of chi-square of 1.273 and a critical value of 13.388?

A) Do not reject the null hypothesis
B) Reject the null hypothesis
C) Unable to reject or not reject the null hypothesis based on data
D) Should take a larger sample
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50
Three new colors have been proposed for the Jeep Grand Cherokee vehicle. They are silvered-blue, almond, and willow green. The null hypothesis for a goodness-of-fit test would be

A) willow green is preferred over the other colors.
B) that there is no preference between the colors.
C) any one color is preferred over the other colors.
D) impossible to determine.
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51
The chi-square statistic has

A) one distribution.
B) two distributions.
C) a family of distributions.
D) a uniform distribution.
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52
Which of the following are correct statements regarding the chi-square distribution?

A) Distribution is negatively skewed.
B) Chi-square is based on two sets of degrees of freedom, one for the numerator and one for the denominator.
C) Its shape is based on the degrees of freedom.
D) The variance is equal to one.
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53
The chi-square distribution becomes more symmetrical as

A) number of variables increase.
B) the chi-square value increases.
C) degrees of freedom decrease.
D) degrees of freedom increase.
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54
Which of the following assumptions is necessary to apply a goodness-of-fit test?

A) Normal population is required.
B) The data are measured with a nominal or ordinal scale.
C) Population variance must be known.
D) Both "a" and "c".
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55
The chi-square distribution is

A) positively skewed.
B) negatively skewed.
C) normally distributed.
D) negatively or positively skewed.
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56
What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?

A) 3.841
B) 5.991
C) 7.815
D) 11.070
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57
For any chi-square goodness-of-fit problem, the number of degrees of freedom is found by

A) n - k - 1.
B) k - 1.
C) n + 1.
D) n + k.
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58
A distributor of personal computers has five locations in the city. The sales in units for the first quarter of the year were as follows: <strong>A distributor of personal computers has five locations in the city. The sales in units for the first quarter of the year were as follows:   What is the critical value at the 0.01 level of risk?</strong> A) 7.779 B) 15.033 C) 13.277 D) 5.412 What is the critical value at the 0.01 level of risk?

A) 7.779
B) 15.033
C) 13.277
D) 5.412
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59
For people released from prison, the following table shows their adjustment to civilian life and place of residence. <strong>For people released from prison, the following table shows their adjustment to civilian life and place of residence.   What is the critical value for this contingency table at the 0.01 level of significance?</strong> A) 9.488 B) 2.070 C) 11.345 D) 13.277 What is the critical value for this contingency table at the 0.01 level of significance?

A) 9.488
B) 2.070
C) 11.345
D) 13.277
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60
Two chi-square distributions were plotted on the same chart. One distribution was for 3 degrees of freedom and the other was for 12 degrees of freedom. Which distribution would tend to approach a normal distribution?

A) 3 degrees
B) 12 degrees
C) 15 degrees
D) All would
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61
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the expected frequency?</strong> A) 9 B) 10 C) 11 D) 12 What is the expected frequency?

A) 9
B) 10
C) 11
D) 12
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62
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What kind of frequencies are the numbers 12, 9, 11, 10, 9, and 9 called?</strong> A) Acceptance B) Critical value C) Expected D) Observed What kind of frequencies are the numbers 12, 9, 11, 10, 9, and 9 called?

A) Acceptance
B) Critical value
C) Expected
D) Observed
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63
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   Using 0.05 as the significance level, what is the critical value for the test statistic?</strong> A) 9.488 B) 5.991 C) 7.815 D) 3.841 Using 0.05 as the significance level, what is the critical value for the test statistic?

A) 9.488
B) 5.991
C) 7.815
D) 3.841
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64
For a chi-square test involving a contingency table, suppose the null hypothesis is rejected. We conclude that the two variables are

A) linear.
B) curvilinear.
C) not related.
D) related.
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65
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   Based on the analysis, what can be concluded?</strong> A) Social activity and education are correlated. B) Social activity and education are not related. C) Social activity and education are related. D) No conclusion is possible. Based on the analysis, what can be concluded?

A) Social activity and education are correlated.
B) Social activity and education are not related.
C) Social activity and education are related.
D) No conclusion is possible.
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66
The computed chi-square value is positive because the difference between the observed and expected frequencies is

A) squared.
B) linear.
C) uniform.
D) always positive.
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67
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The appropriate test statistic for the analysis is a:</strong> A) F-statistic B) T-statistic C) Chi-square statistic D) Z-statistic The appropriate test statistic for the analysis is a:

A) F-statistic
B) T-statistic
C) Chi-square statistic
D) Z-statistic
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68
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The null hypothesis for the analysis is:</strong> A) There is no relationship between social activity and education. B) The correlation between social activity and education is zero. C) As social activity increases, education increases. D) The mean of social activity equals the mean of education. The null hypothesis for the analysis is:

A) There is no relationship between social activity and education.
B) The correlation between social activity and education is zero.
C) As social activity increases, education increases.
D) The mean of social activity equals the mean of education.
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69
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   How many degrees of freedom are there?</strong> A) 0 B) 3 C) 4 D) 5 How many degrees of freedom are there?

A) 0
B) 3
C) 4
D) 5
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70
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   The null hypothesis for the analysis is:</strong> A) There is no relationship between gender and driving behavior. B) The correlation between driving behavior and gender is zero. C) As driving behavior increases, gender increases. D) The mean of driving behavior equals the mean of gender. The null hypothesis for the analysis is:

A) There is no relationship between gender and driving behavior.
B) The correlation between driving behavior and gender is zero.
C) As driving behavior increases, gender increases.
D) The mean of driving behavior equals the mean of gender.
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71
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the calculated value of chi-square?</strong> A) 1.0 B) 0.5 C) 0.8 D) 8.0 What is the calculated value of chi-square?

A) 1.0
B) 0.5
C) 0.8
D) 8.0
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72
Which of the following can be used to test the hypothesis that two nominal variables are related?

A) a contingency table.
B) a chi-square table.
C) an ANOVA table.
D) a scatter diagram.
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73
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The appropriate test to analyze the relationship between social activity and education is:</strong> A) Regression analysis B) Analysis of variance C) Contingency table analysis D) Goodness-of-fit The appropriate test to analyze the relationship between social activity and education is:

A) Regression analysis
B) Analysis of variance
C) Contingency table analysis
D) Goodness-of-fit
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74
A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:  <strong>A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:   What is the critical value of chi-square with  \alpha  = 0.05?</strong> A) 11.070 B) 12.592 C) 13.388 D) 15.033
What is the critical value of chi-square with α\alpha = 0.05?

A) 11.070
B) 12.592
C) 13.388
D) 15.033
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75
When determining how well an observed set of frequencies fit an expected set of frequencies, what is the test statistic?

A) F-statistic.
B) t-statistic.
C) <strong>When determining how well an observed set of frequencies fit an expected set of frequencies, what is the test statistic?</strong> A) F-statistic. B) t-statistic. C)   statistic. D) z-statistic. statistic.
D) z-statistic.
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76
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   The degrees of freedom for the analysis is:</strong> A) 1 B) 2 C) 3 D) 4 The degrees of freedom for the analysis is:

A) 1
B) 2
C) 3
D) 4
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77
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   The degrees of freedom for the analysis is:</strong> A) 1 B) 2 C) 3 D) 4 The degrees of freedom for the analysis is:

A) 1
B) 2
C) 3
D) 4
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78
A recent study of the relationship between social activity and education showed the following results. <strong>A recent study of the relationship between social activity and education showed the following results.   What is the value of the test statistic?</strong> A) 100 B) 83.67 C) 50 D) 4.94 What is the value of the test statistic?

A) 100
B) 83.67
C) 50
D) 4.94
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79
In a goodness-of-fit test, the null hypothesis (no difference between sets of observed and expected frequencies) is rejected when the

A) computed chi-square is less than the critical value.
B) difference between the observed and expected frequencies is significantly large.
C) difference between the observed and expected frequencies is small.
D) difference between the observed and expected frequencies occurs by chance.
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80
Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students: <strong>Recently, students in a marketing research class were interested in the driving behavior of students. Specifically, the marketing students were interested if exceeding the speed limit was related to social activity. They collected the following responses from 100 randomly selected students:   Using 0.05 as the significance level, what is the critical value for the test statistic?</strong> A) 9.488 B) 5.991 C) 7.815 D) 3.841 Using 0.05 as the significance level, what is the critical value for the test statistic?

A) 9.488
B) 5.991
C) 7.815
D) 3.841
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