Each plate of a parallel-plate air-filled capacitor has an area of 0.0020 m², and the separation of the plates is 0.020 mm. An electric field of 3.9 x 10⁶ V/m is present between the plates. What is the surface charge density on the plates? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A) 35 µC/m² B) 73 µC/m² C) 17 µC/m² D) 52 µC/m² E) 87 µC/m²

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Quizplus · Accepted Answer

The surface charge density is given by:σ = ε₀Ewhere:σ is the surface charge density (C/m²)ε₀ is the permittivity of free space (8.85 × 10^-12 C²/N ∙ m²)E is the electric field (V/m)Substituting the given values into the equation, we get:σ = (8.85 × 10^-12 C²/N ∙ m²)(3.9 × 10^6 V/m) = 35 µC/m²Therefore, the surface charge density on the plates is 35 µC/m².

Each Plate of a Parallel-Plate Air-Filled Capacitor Has an Area