If the name of the input file was in a variable named filename, which of the following is the correct way to open the input stream named inFile and associate it with this file?
A) inFile.openfilename);
B) inFile=filename;
C) inFile="filename";
D) inFile.open"filename");

Question

Quizplus · Accepted Answer

Option A is correct because the syntax for opening a file using an ifstream object (in this case, inFile) involves calling the open method with the filename as its argument. The correct syntax is inFile.open(filename); where filename is a variable containing the name of the file.

If the Name of the Input File Was in a Variable