If the name of a file to open is in the string variable name fileName, which of the following will correctly open the file for output?
A) out_file.openfileName);
B) out_file.open"fileName");
C) fileName.openoutfile);
D) out_file.openfileName.c_str));

Question

Quizplus · Accepted Answer

The correct syntax for opening a file for output is out_file.open(fileName.c_str()). Option D correctly uses the variable fileName and converts it to a C-style string using the c_str() function before passing it to the open() function.

If the Name of a File to Open Is in the String