A gene in a randomly-mating population has two alleles (A,a),and 1 in 400 individuals in the population is homozygous recessive (aa).Calculate the frequency of heterozygotes (Aa)in the population.

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Quizplus · Accepted Answer

The frequency of homozygous recessive (aa) is q^2 = 1/400 = 0.0025, so q = √0.0025 = 0.05. The frequency of the dominant allele (p) is 1 - q = 0.95. The frequency of heterozygotes (Aa) is 2pq = 2(0.95)(0.05) = 0.095.

A Gene in a Randomly-Mating Population Has Two Alleles (A,a),and