The following two methods will both compute the same thing when invoked with the same value of x. That is, method1(x) = = method2(x).
public int method1(int x)
{
if (x 0) return method1(x - 1) + 1;
else return 0;
}
public int method2(int x)
{
if (x 0) return 1 + method2(x - 1);
else return 0;
}

Question

The following two methods will both compute the same thing when invoked with the same value of x. That is, method1(x) = = method2(x).
public int method1(int x)
{
if (x > 0) return method1(x - 1) + 1;
else return 0;
}
public int method2(int x)
{
if (x > 0) return 1 + method2(x - 1);
else return 0;
}

Quizplus · Accepted Answer

The two methods both use recursion to add 1 to the result of calling the method with x - 1 until x reaches 0. The order in which the addition and recursive call are performed is different, but the end result is the same.

The Following Two Methods Will Both Compute the Same Thing