The standard oxidation potential, $E_{o x}^{\circ}$ ,of Cu(s)is ?0.339 V.The oxidation product is the copper(II)ion.Write the equation for the standard reduction potential.What is the value of the standard reduction potential, ${E}_{\text {red }}^{0}$ ?

Question

Quizplus · Accepted Answer

The equation for the standard reduction potential is the reverse of the oxidation half-reaction, so we need to flip the given equation and reverse the sign of the potential: Cu(s) + 2e- → Cu2+(aq) (reduction)
The standard reduction potential is equal in magnitude but opposite in sign to the standard oxidation potential, so ${E}_{\text {red }}^{0}$ = +0.339 V. Choice B correctly shows the reversed reduction reaction and the positive value for ${E}_{\text {red }}^{0}$.

The Standard Oxidation Potential Eox∘E_{o x}^{\circ}Eox∘​ ,Of Cu(s)is ?0 Ered 0{E}_{\text {red }}^{0}Ered 0​

The Standard Oxidation Potential $E_{o x}^{\circ}$ ,Of Cu(s)is ?0 ${E}_{\text {red }}^{0}$