Ammonia is synthesized from nitrogen and hydrogen gases. N₂(g) + 3H₂(g) → 2NH₃(g)
If ΔH° = −92.2 kJ and ΔS° = −0.1987 kJ/K,at what temperature will ΔG° = 0?

Question

Ammonia is synthesized from nitrogen and hydrogen gases. N₂(g)+ 3H₂(g)→ 2NH₃(g) If ΔH° = −92.2 kJ and ΔS° = −0.1987 kJ/K,at what temperature will ΔG° = 0?

Quizplus · Accepted Answer

The equation for free energy change is:

ΔG° = ΔH° - TΔS°

At equilibrium, ΔG° = 0, so we can rearrange the equation as:

T = ΔH°/ΔS°

Substituting the given values, we get:

T = (-92.2 kJ) / (-0.1987 kJ/K) = 464 K

Therefore, the temperature at which ΔG° = 0 is 464 K. The correct answer is D.

Ammonia Is Synthesized from Nitrogen and Hydrogen Gases