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Which of the Following Equations Is the Henderson-Hasselbalch Equation?
A) pH=pKa+log[H+][B]\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}+\log \frac{\left[\mathrm{H}^{+}\right]}{\left[\mathrm{B}^{-}\right]}

Question 2

Multiple Choice

Which of the following equations is the Henderson-Hasselbalch equation?


A) pH=pKa+log[H+][B]\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}+\log \frac{\left[\mathrm{H}^{+}\right]}{\left[\mathrm{B}^{-}\right]}
B) pH=pKalog[B][HB]\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}-\log \frac{\left[\mathrm{B}^{-}\right]}{[\mathrm{HB}]}
C) pH=pKa+log[B][HB]\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}+\log \frac{\left[\mathrm{B}^{-}\right]}{[\mathrm{HB}]}
D) pKa=pH+log[B][HB]\mathrm{p} K_{\mathrm{a}}=\mathrm{pH}+\log \frac{\left[\mathrm{B}^{-}\right]}{[\mathrm{HB}]}
E) pKa=pHlog[OH][H+]\mathrm{p} K_{\mathrm{a}}=\mathrm{pH}-\log \frac{\left[\mathrm{OH}^{-}\right]}{\left[\mathrm{H}^{+}\right]}

Correct Answer:

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