The K_a for hydrofluoric acid is 6.9 × 10−⁴.What is K_b for fluoride ion?

Name: The K a for hydrofluoric acid is 6.9 × 10− 4 .What is K b for fluoride ion?
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The relationship between K_a and K_b for a conjugate acid-base pair is given by the equation K_w = K_a × K_b, where K_w is the ion product of water (1.0 × 10⁻¹⁴ at 25°C). Solving for K_b gives K_b = K_w / K_a = (1.0 × 10⁻¹⁴) / (6.9 × 10⁻⁴) = 1.4 × 10⁻¹¹.

The Ka for Hydrofluoric Acid Is 6

The K_a for Hydrofluoric Acid Is 6