Calcium carbonate decomposes to calcium oxide and carbon dioxide.
The equilibrium constant for this reaction is 9.7 × 10−24 at 298 K.What is the equilibrium constant at 575 K? (R = 8.31 J/mol⋅K)
A) 7.5 × 10−16
B) 1.3 × 10−8
C) 1.4 × 1038
D) 1.3 × 1015
E) 1.0 × 1023
Correct Answer:
Verified
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