The rate constant for the decomposition of cyclobutane is 2.08 × 10−² s−¹ at high temperatures. C₄H₈(g) → 2C₂H₄(g)
How many seconds are required for an initial concentration of 0.100 M C₄H₈(g) to decrease to 0.0450 M?

Question

Quizplus · Accepted Answer

The rate law can be written as: rate = k[C₄H₈] Integrated rate law for first-order reactions is: ln([A]t/[A]0) = -kt Rearranging the equation and plugging in the given values, we get: ln(0.0450/0.100) = (-2.08 × 10^-12 s^-1)(t) t = 38.4 s

The Rate Constant for the Decomposition of Cyclobutane Is 2