When Cs-137 decays,it emits gamma radiation.The energy of one photon is 1.06 × 10−¹³ J.What is the wavelength of this radiation?

Question

Quizplus · Accepted Answer

The wavelength of the radiation can be calculated using the equation $c = \lambda \nu$, where $c$ is the speed of light, $\lambda$ is the wavelength, and $\nu$ is the frequency. The energy of a photon can be calculated using $E = h\nu$, where $h$ is Planck's constant. Rearranging for $\lambda$, we get $\lambda = \frac{hc}{E}$. Substituting $h = 6.626 \times 10^{-34}$ J·s, $c = 3.00 \times 10^8$ m/s, and $E = 1.06 \times 10^{-13}$ J, we find $\lambda \approx 1.87 \times 10^{-12}$ m.

When Cs-137 Decays,it Emits Gamma Radiation