What volume of 0.250 M KCl(aq)will completely react with 50.0 mL of 0.115 M Pb(NO₃)₂(aq)? Pb²⁺(aq)+ 2Cl−(aq)→ PbCl₂(s)

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The balanced chemical equation is Pb^2+ + 2Cl^- → PbCl2. From the equation, 1 mole of Pb^2+ reacts with 2 moles of Cl^-. The moles of Pb^2+ in 50.0 mL of 0.115 M solution is (0.115 mol/L) * (0.050 L) = 0.00575 mol. To react completely with Pb^2+, we need 2 times the moles of Cl^-, which is 2 * 0.00575 mol = 0.0115 mol of Cl^-. The volume of 0.250 M KCl needed is (0.0115 mol) / (0.250 mol/L) = 0.046 L, or 46.0 mL.

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