In the laboratory,acid spills are often neutralized by adding sodium bicarbonate.What mass of sodium bicarbonate reacts with 225 mL of 6.00 M HCl?
H⁺(aq) + NaHCO₃(s) → H₂O(l) + CO₂(g) + Na⁺(aq)

Question

Quizplus · Accepted Answer

To find the mass of sodium bicarbonate needed, first calculate the moles of HCl: 225 mL * 6.00 M = 1.35 moles of HCl. The reaction is 1:1, so 1.35 moles of NaHCO₃ are needed. The molar mass of NaHCO₃ is about 84 g/mol. Therefore, 1.35 moles * 84 g/mol = 113.4 g, which rounds to 113 g.

In the Laboratory,acid Spills Are Often Neutralized by Adding Sodium