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Which Is a Correct Method for Determining the Mass of Carbon

Question 34

Multiple Choice

Which is a correct method for determining the mass of carbon present in 0.132 grams of propane (C3H8) ?


A) 0.132 gC3H8(1 molC3H844.09 g) (12.01 gC1 mole) 0.132 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}\left(\frac{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}{44.09 \mathrm{~g}}\right) \left(\frac{12.01 \mathrm{~g} \mathrm{C}}{1 \mathrm{~mole}}\right)
B) 0.132 gC3H8(1 molC3H844.09 g) 0.132 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}\left(\frac{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}{44.09 \mathrm{~g}}\right) (3gC1 molC3H8) \left(\frac{3 \mathrm{gC}}{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}\right)
C) 0.132 gC3H8(44.09 molC3H81 g) 0.132 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}\left(\frac{44.09 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}{1 \mathrm{~g}}\right) (3 molC1 molC3H8) (12.01gC1 mole) \left(\frac{3 \mathrm{~mol} \mathrm{C}}{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}\right) \left(\frac{12.01 \mathrm{gC}}{1 \mathrm{~mole}}\right)
D) 0.132 gC3H8(1 molC3H844.09 g) 0.132 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}\left(\frac{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}{44.09 \mathrm{~g}}\right) (1 molC3 molC3H8) (12.01 gC1 mole) \left(\frac{1 \mathrm{~mol} \mathrm{C}}{3 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}\right) \left(\frac{12.01 \mathrm{~g} \mathrm{C}}{1 \mathrm{~mole}}\right)
E) 0.132 gC3H8(1 molC3H844.09 g) 0.132 \mathrm{~g} \mathrm{C}_{3} \mathrm{H}_{8}\left(\frac{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}{44.09 \mathrm{~g}}\right) (3 molC1 molC3H8) (12.01gC1 mole) \left(\frac{3 \mathrm{~mol} \mathrm{C}}{1 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}}\right) \left(\frac{12.01 \mathrm{gC}}{1 \mathrm{~mole}}\right)

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