Solved

Which Method Is Correct for Converting Kelvin to Celsius?
A) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right)=\left(\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K})+32$

Question 11

Multiple Choice

Which method is correct for converting kelvin to Celsius?

A) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right) =\left(\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K}) +32$
B) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right) =\left(\frac{9^{\circ} \mathrm{C}}{5 \mathrm{~K}}\right) \mathrm{T}(\mathrm{K}) +273.15$
C) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right) =\frac{5^{\circ} \mathrm{C}}{9 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K}) -273.15)$
D) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right) =\frac{1^{\circ} \mathrm{C}}{1 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K}) -273.15)$
E) $\mathrm{T}\left({ }^{\circ} \mathrm{C}\right) =\frac{1^{\circ} \mathrm{C}}{1 \mathrm{~K}}(\mathrm{~T}(\mathrm{~K}) +273.15)$