What mass of sulfur dioxide gas is produced from 5.50 kg of coal that contains 1.37 % sulfur by mass?

Question

Quizplus · Accepted Answer

First, we need to determine the amount of sulfur in 5.50 kg of coal:

Sulfur amount = 5.50 kg x 0.0137 = 0.07535 kg

Next, we can use the balanced chemical equation for the combustion of coal to sulfur dioxide to determine the amount of sulfur dioxide produced:

C(s) + O2(g) + S(s) → SO2(g)

From the equation, we can see that 1 mole of sulfur produces 1 mole of sulfur dioxide. The molar mass of sulfur is 32.07 g/mol, so the number of moles of sulfur in 0.07535 kg can be calculated as:

moles of S = (0.07535 kg) / (32.07 g/mol) = 0.002348 mol

Therefore, the mass of sulfur dioxide produced can be calculated as:

mass of SO2 = (0.002348 mol) x (64.06 g/mol) = 0.1504 g or 151 g to three significant figures.

What Mass of Sulfur Dioxide Gas Is Produced from 5