Hydrogen peroxide decomposes into water and oxygen in a first-order process. H₂O₂(aq) → H₂O( ) + 1/2 O₂(g)
At 20.0 °C,the half-life for the reaction is 3.92 × 10⁴ seconds.If the initial concentration of hydrogen peroxide is 0.52 M,what is the concentration after 7.00 days?

Question

Hydrogen peroxide decomposes into water and oxygen in a first-order process. H₂O₂(aq) → H₂O(

Hydrogen peroxide decomposes into water and oxygen in a first-order process. H<sub>2</sub>O<sub>2</sub>(aq) → H<sub>2</sub>O( ) + 1/2 O<sub>2</sub>(g) At 20.0 °C,the half-life for the reaction is 3.92 × 10<sup>4</sup> seconds.If the initial concentration of hydrogen peroxide is 0.52 M,what is the concentration after 7.00 days? A) 1.2 × 10<sup>-5</sup> M B) 0.034 M C) 0.074 M D) 0.22 M E) 0.52 M

) + 1/2 O₂(g)
At 20.0 °C,the half-life for the reaction is 3.92 × 10⁴ seconds.If the initial concentration of hydrogen peroxide is 0.52 M,what is the concentration after 7.00 days?

Quizplus · Accepted Answer

The Answer of Hydrogen peroxide decomposes into water and oxygen in a first-order process. H₂O₂(aq)→ H₂O( )+ 1/2 O₂(g) At 20.0 °C,the half-life for the reaction is 3.92 × 10⁴ seconds.If the initial concentration of hydrogen peroxide is 0.52 M,what is the concentration after 7.00 days?

Hydrogen Peroxide Decomposes into Water and Oxygen in a First-Order