The rate constant for a reaction at 40.0°C is exactly 6 times that at 20.0°C.Calculate the Arrhenius energy of activation for the reaction.(R = 8.314 J/K⋅mol)

Question

Quizplus · Accepted Answer

Using the Arrhenius equation, k = A * exp(-Ea/(RT)), and the given information that k2/k1 = 6, we can set up the equation: ln(6) = Ea/R * (1/T1 - 1/T2). Substituting T1 = 293 K and T2 = 313 K, and solving for Ea gives approximately 68.3 kJ/mol.

The Rate Constant for a Reaction at 40