Let s(t) = t⁹ -t be a position function of a particle. At 1 the particle's acceleration is A) negative B) positive C) zero

Question

Quizplus · Accepted Answer

The acceleration of the particle is given by the second derivative of the position function, which is:
s''(t) = 2S1U1P19S1S1F1F1S1-F1F1F1S1
When t = 1, the acceleration is:
s''(1) = 2S1U1P19S1S1F1F1S1-F1F1F1S1
Since S1, U1, P19, F1, and F10 are all constants, the acceleration at t = 1 is also a constant value. Without knowing the specific values of these constants, we cannot determine the sign of the acceleration. However, we can conclude that the answer is either A or B, as the acceleration is non-zero. Since it is impossible for the acceleration to be zero, the best choice is B, positive.

Let S(t) = T9 -T Be a Position Function of a Particle

Let S(t) = T⁹ -T Be a Position Function of a Particle