An object in orbit has r_max = 10²⁴km and e = 0.27. Find r_min. A) 5.75 * 10²³km B) 6.32 *10²³km C) 5.46 *10²³km D) 5.75 *10²⁶km E) 6.32 * 10²⁶km

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Quizplus · Accepted Answer

The minimum distance $r_{min}$ in an elliptical orbit is given by $r_{min} = r_{max} \times \frac{1 - e}{1 + e}$, where $r_{max}$ is the maximum distance and $e$ is the eccentricity. Substituting $r_{max} = 10^{24}km$ and $e = 0.27$, we get $r_{min} = 10^{24}km \times \frac{1 - 0.27}{1 + 0.27} = 5.75 \times 10^{23}km$.

An Object in Orbit Has Rmax = 1024km and E

An Object in Orbit Has R_max = 10²⁴km and E