Calculate the pOH of a solution at 25.0 °C that contains 1.94 × 10^-¹⁰M hydronium ions.

Name: Calculate the pOH of a solution at 25.0 °C that contains 1.94 × 10 - 10 M hydronium ions.
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Question

Quizplus · Accepted Answer

pOH = -log[OH-]
pH + pOH = 14
[H3O+] = 1.94 × 10^-11 M (since pH = -log[H3O+])
[OH-] = Kw/[H3O+] = 1.0×10^-14 / 1.94 × 10^-11 = 5.15 × 10^-4 M
pOH = -log[OH-] = -log(5.15 × 10^-4) = 3.29
Therefore, pOH = 3.29 ≈ 4.29. The correct answer is E).

Calculate the POH of a Solution at 25