What is the value of X after the instructions corresponding to the following pseudocode are executed?
$$\begin{array} { l }
\mathrm { X } = 5 \
\mathrm { Y } = 7
\end{array}$$
IF $\operatorname { INT } ( 5.4 ) = \mathrm { X }$ AND INT(6.9) $= \mathrm { Y }$ THEN $\mathrm { X } = \mathrm { X } + \mathrm { Y }$
ELSE
$$\mathrm { Y } = \mathrm { Y } + 1$$
ENDIF
A)5
B)7
C)8
D)12

Question

What is the value of X after the instructions corresponding to the following pseudocode are executed?
$$\begin{array} { l } 
\mathrm { X } = 5 \
\mathrm { Y } = 7
\end{array}$$
IF $\operatorname { INT } ( 5.4 ) = \mathrm { X }$ AND INT(6.9) $= \mathrm { Y }$ THEN $\mathrm { X } = \mathrm { X } + \mathrm { Y }$
ELSE
$$\mathrm { Y } = \mathrm { Y } + 1$$
ENDIF
A)5
B)7
C)8
D)12

Quizplus · Accepted Answer

The condition in the IF statement is false because INT(6.9) does not equal Y (7). Therefore, the ELSE part is executed, incrementing Y by 1, but X remains unchanged at 5.

What Is the Value of X After the Instructions Corresponding X=5Y=7\begin{array} { l } \mathrm { X } = 5 \\\mathrm { Y } = 7\end{array}X=5Y=7​

What Is the Value of X After the Instructions Corresponding $\begin{array} { l } \mathrm { X } = 5 \\\mathrm { Y } = 7\end{array}$