A recent analysis of the number of rainy days per month found the following outcomes and probabilities. $$\begin{array} { | c | c | }
\hline \text { Namber of Raining Days } ( x ) & \mathrm { P } ( x ) \
\hline \hline 3 & .40 \
\hline 4 & .20 \
\hline 5 & .40 \
\hline
\end{array}$$ The mean of this distribution is _____________.
A)2
B)3
C)4
D)5
E)

Question

A recent analysis of the number of rainy days per month found the following outcomes and probabilities. $$\begin{array} { | c | c | } 
\hline \text { Namber of Raining Days } ( x ) & \mathrm { P } ( x ) \
\hline \hline 3 & .40 \
\hline 4 & .20 \
\hline 5 & .40 \
\hline
\end{array}$$ The mean of this distribution is _____________.
A)2
B)3
C)4
D)5
E)<1

Quizplus · Accepted Answer

The mean of the distribution is calculated by multiplying each outcome by its probability and summing these products: $3(.40) + 4(.20) + 5(.40) = 1.2 + 0.8 + 2 = 4$.

A Recent Analysis of the Number of Rainy Days Per