The thermochemical equation for the combustion of methanol is given below. CH₃OH( $\ell$ ) + 3/2 O₂(g) ? CO₂(g) + 2 H ₂O(g)
?_rH° = -638.7 kJ/mol-rxn
What is the enthalpy change for the combustion of 8.59 g of CH₃OH?

Question

The thermochemical equation for the combustion of methanol is given below. CH₃OH(

\ell

) + 3/2 O₂(g) ? CO₂(g) + 2 H ₂O(g)
?_rH° = -638.7 kJ/mol-rxn
What is the enthalpy change for the combustion of 8.59 g of CH₃OH?

Quizplus · Accepted Answer

The molar mass of CH₃OH is 32.04 g/mol. For 8.59 g of CH₃OH, the moles are 8.59 g / 32.04 g/mol = 0.268 mol. The enthalpy change is 0.268 mol × (-638.7 kJ/mol) = -171 kJ.

The Thermochemical Equation for the Combustion of Methanol Is Given ℓ\ellℓ

The Thermochemical Equation for the Combustion of Methanol Is Given $\ell$