An ideal Carnot heat engine operates between $285 \mathrm {~K}$ and $460 \mathrm {~K}$ What is its efficiency?
A)0.38
B)0.62
C)0.61
D)1.61

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by $1 - \frac{T_c}{T_h}$, where $T_c$ is the cold reservoir temperature and $T_h$ is the hot reservoir temperature. Substituting the given values: $1 - \frac{285}{460} = 0.3804$, which is approximately 0.38.

An Ideal Carnot Heat Engine Operates Between 285 K285 \mathrm {~K}285 K And 460 K460 \mathrm {~K}460 K

An Ideal Carnot Heat Engine Operates Between $285 \mathrm {~K}$ And $460 \mathrm {~K}$