Assume a transistor has a maximum power rating of 1 W and VCE = 5 V. If IC = 120 mA, the power rating is not exceeded.

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Quizplus · Accepted Answer

The power rating is not exceeded because the power dissipated by the transistor is less than the maximum power rating. The power dissipated by the transistor is given by the equation P = VCE * IC, where VCE is the collector-emitter voltage and IC is the collector current. In this case, VCE = 5 V and IC = 120 mA, so the power dissipated by the transistor is P = 5 V * 120 mA = 600 mW, which is less than the maximum power rating of 1 W.

Assume a Transistor Has a Maximum Power Rating of 1