Assume that y is directly proportional to x.Use the given x-value and y-value to find a linear model that relates y and x.
$x = 38 , y = 2400$

A)y = $\frac { 1200 } { 19 }$ x
B)y = - 2400x
C)y = $\frac { 19 } { 1200 }$ x
D)y = - $\frac { 19 } { 1200 }$ x
E)y = - $\frac { 1200 } { 19 }$ x

Question

Assume that y is directly proportional to x.Use the given x-value and y-value to find a linear model that relates y and x. 
 $x = 38 , y = 2400$ 
 
A)y = $\frac { 1200 } { 19 }$ x
B)y = - 2400x
C)y = $\frac { 19 } { 1200 }$ x
D)y = - $\frac { 19 } { 1200 }$ x 
E)y = - $\frac { 1200 } { 19 }$ x

Quizplus · Accepted Answer

Since y is directly proportional to x, the relationship can be modeled as $y = kx$, where $k$ is the constant of proportionality. Given $x = 38$ and $y = 2400$, we can solve for $k$ as $k = \frac{y}{x} = \frac{2400}{38} = \frac{1200}{19}$. Thus, the model is $y = \frac{1200}{19}x$.

Assume That Y Is Directly Proportional to X x=38,y=2400x = 38 , y = 2400x=38,y=2400

Assume That Y Is Directly Proportional to X $x = 38 , y = 2400$