Find the zeros (if any) of the rational function. $g ( x ) = \frac { x ^ { 3 } - 8 } { x ^ { 2 } + 1 }$
A)8
B)-8
C) 2
D)-1
E)- 2

Question

Find the zeros (if any) of the rational function.   $g ( x ) = \frac { x ^ { 3 } - 8 } { x ^ { 2 } + 1 }$  
A)8
B)-8
C) 2
D)-1
E)- 2

Quizplus · Accepted Answer

The zeros of the rational function $g(x) = \frac{x^3 - 8}{x^2 + 1}$ are found by setting the numerator equal to zero and solving for $x$. The equation $x^3 - 8 = 0$ simplifies to $x^3 = 8$, which has the solution $x = 2$. The denominator $x^2 + 1$ does not affect the zeros since it cannot be zero (it's always positive).

Find the Zeros (If Any) of the Rational Function g(x)=x3−8x2+1g ( x ) = \frac { x ^ { 3 } - 8 } { x ^ { 2 } + 1 }g(x)=x2+1x3−8​

Find the Zeros (If Any) of the Rational Function $g ( x ) = \frac { x ^ { 3 } - 8 } { x ^ { 2 } + 1 }$