Determine the zeros (if any) of the rational function $f ( x ) = \frac { x ^ { 2 } - 4 } { x + 3 }$ .
A)no zeros
B) $x = - \frac { 2 } { 3 } , x = \frac { 2 } { 3 }$
C) x = -3
D) x = -4, x = 4
E) x = -2, x = 2

Question

Determine the zeros (if any) of the rational function $f ( x ) = \frac { x ^ { 2 } - 4 } { x + 3 }$ .
A)no zeros
B) $x = - \frac { 2 } { 3 } , x = \frac { 2 } { 3 }$
C) x = -3
D) x = -4,  x = 4
E) x = -2,  x = 2

Quizplus · Accepted Answer

The zeros of the function are found by setting the numerator equal to zero and solving for $x$. The numerator is $x^2 - 4$, which factors to $(x - 2)(x + 2) = 0$, giving zeros at $x = -2$ and $x = 2$.

Determine the Zeros (If Any) of the Rational Function f(x)=x2−4x+3f ( x ) = \frac { x ^ { 2 } - 4 } { x + 3 }f(x)=x+3x2−4​

Determine the Zeros (If Any) of the Rational Function $f ( x ) = \frac { x ^ { 2 } - 4 } { x + 3 }$