Write the complex number in standard form. $\sqrt { - 6 } \cdot \sqrt { - 7 }$
A) - $\sqrt { 6 }$
B) $\sqrt { 7 }$
C) $\sqrt { 6 }$
D)- $\sqrt { 42 }$
E) $\sqrt { 42 }$

Question

Write the complex number in standard form.   $\sqrt { - 6 } \cdot \sqrt { - 7 }$  
A) - $\sqrt { 6 }$
B) $\sqrt { 7 }$
C) $\sqrt { 6 }$
D)- $\sqrt { 42 }$
E) $\sqrt { 42 }$

Quizplus · Accepted Answer

The product of two square roots of negative numbers is the square root of their product times $i^2$, which is -1. Thus, $\sqrt{-6} \cdot \sqrt{-7} = \sqrt{42} \cdot i^2 = -\sqrt{42}$.

Write the Complex Number in Standard Form −6⋅−7\sqrt { - 6 } \cdot \sqrt { - 7 }−6​⋅−7​

Write the Complex Number in Standard Form $\sqrt { - 6 } \cdot \sqrt { - 7 }$