Use synthetic division to divide.
$\left( 4 x ^ { 3 } - 8 x + 24 x ^ { 2 } - 48 \right) \div ( x + 6 )$
A) $4 x ^ { 2 } - 8 , x \neq - 6$
B) $4 x ^ { 2 } + 8 , x \neq - 6$
C) $- 4 x ^ { 2 } - 8 , x \neq - 6$
D) $4 x ^ { 3 } - 8 , x \neq - 6$
E) $4 x ^ { 3 } + 8 , x \neq - 6$

Question

Use synthetic division to divide. 
 $\left( 4 x ^ { 3 } - 8 x + 24 x ^ { 2 } - 48 \right) \div ( x + 6 )$  
A) $4 x ^ { 2 } - 8 , x \neq - 6$
B) $4 x ^ { 2 } + 8 , x \neq - 6$
C) $- 4 x ^ { 2 } - 8 , x \neq - 6$
D) $4 x ^ { 3 } - 8 , x \neq - 6$
E) $4 x ^ { 3 } + 8 , x \neq - 6$

Quizplus · Accepted Answer

The correct division using synthetic division with $x + 6$ (which means using -6 in synthetic division) gives $4x^2 - 8x + 24 - 8$, where the $x^2$, $x$, and constant terms are the result of the division, and there is no remainder.

Use Synthetic Division to Divide (4x3−8x+24x2−48)÷(x+6)\left( 4 x ^ { 3 } - 8 x + 24 x ^ { 2 } - 48 \right) \div ( x + 6 )(4x3−8x+24x2−48)÷(x+6)

Use Synthetic Division to Divide $\left( 4 x ^ { 3 } - 8 x + 24 x ^ { 2 } - 48 \right) \div ( x + 6 )$