Solve the logarithmic equation algebraically.Approximate the result to three decimal places. $\ln 2 x = 3$
A) $\frac { e ^ { 3 } } { 2 } \approx 8.043$
B) $\frac { e ^ { 3 } } { 2 } \approx 10.043$
C) $\frac { e ^ { 3 } } { 2 } \approx 12.043$
D) $\frac { e ^ { 3 } } { 2 } \approx 11.043$
E) $\frac { e ^ { 3 } } { 2 } \approx 13.043$

Question

Solve the logarithmic equation algebraically.Approximate the result to three decimal places.  $\ln 2 x = 3$ 
A) $\frac { e ^ { 3 } } { 2 } \approx 8.043$
B) $\frac { e ^ { 3 } } { 2 } \approx 10.043$
C) $\frac { e ^ { 3 } } { 2 } \approx 12.043$
D) $\frac { e ^ { 3 } } { 2 } \approx 11.043$
E) $\frac { e ^ { 3 } } { 2 } \approx 13.043$

Quizplus · Accepted Answer

The Answer of Solve the logarithmic equation algebraically.Approximate the result to three decimal places.  $\ln 2 x = 3$ 
A) $\frac { e ^ { 3 } } { 2 } \approx 8.043$
B) $\frac { e ^ { 3 } } { 2 } \approx 10.043$
C) $\frac { e ^ { 3 } } { 2 } \approx 12.043$
D) $\frac { e ^ { 3 } } { 2 } \approx 11.043$
E) $\frac { e ^ { 3 } } { 2 } \approx 13.043$

Solve the Logarithmic Equation Algebraically ln⁡2x=3\ln 2 x = 3ln2x=3 A) e32≈8.043\frac { e ^ { 3 } } { 2 } \approx 8.0432e3​≈8.043

Solve the Logarithmic Equation Algebraically $\ln 2 x = 3$ A) $\frac { e ^ { 3 } } { 2 } \approx 8.043$