Use the product-to-sum formulas to rewrite the product as a sum or difference. $\sin \frac { \pi } { 3 } \cos \frac { \pi } { 6 }$
A) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$
B) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \sin \frac { \pi } { 6 } \right)$
C) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \cos \frac { \pi } { 6 } \right)$
D) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \sin \frac { \pi } { 6 } \right)$
E) $\left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$

Question

Use the product-to-sum formulas to rewrite the product as a sum or difference.   $\sin \frac { \pi } { 3 } \cos \frac { \pi } { 6 }$  
A)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$
B)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \sin \frac { \pi } { 6 } \right)$
C) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \cos \frac { \pi } { 6 } \right)$
D)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \sin \frac { \pi } { 6 } \right)$
E)  $\left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$

Quizplus · Accepted Answer

The Answer of Use the product-to-sum formulas to rewrite the product as a sum or difference.   $\sin \frac { \pi } { 3 } \cos \frac { \pi } { 6 }$  
A)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$
B)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \sin \frac { \pi } { 6 } \right)$
C) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \cos \frac { \pi } { 6 } \right)$
D)  $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \sin \frac { \pi } { 6 } \right)$
E)  $\left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$

Use the Product-To-Sum Formulas to Rewrite the Product as a Sum