Write an expression for the nth term of the geometric sequence.Then find the indicated term.(Round your answer to three decimal places.) $a _ { 1 } = 7 , r = \sqrt { 3 } , n = 8$
A) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n - 1 }$ , About 15.456
B) $a _ { n } = ( \sqrt { 3 } ) ^ { n - 1 }$ , About 982.073
C) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n + 1 }$ , About 327.358
D) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n - 1 }$ , About 327.358
E) $a _ { n } = ( \sqrt { 3 } ) ^ { n + 1 }$ , About 15.456

Question

Write an expression for the nth term of the geometric sequence.Then find the indicated term.(Round your answer to three decimal places.)   $a _ { 1 } = 7 , r = \sqrt { 3 } , n = 8$  
A) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n - 1 }$ , About 15.456
B) $a _ { n } = ( \sqrt { 3 } ) ^ { n - 1 }$ , About 982.073
C) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n + 1 }$ , About 327.358
D) $a _ { n } = 7 ( \sqrt { 3 } ) ^ { n - 1 }$ , About 327.358
E) $a _ { n } = ( \sqrt { 3 } ) ^ { n + 1 }$ , About 15.456

Quizplus · Accepted Answer

The formula for the nth term of a geometric sequence is $a_n = a_1 \cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio. Substituting $a_1 = 7$ and $r = \sqrt{3}$, we get $a_n = 7(\sqrt{3})^{n-1}$. Calculating the 8th term, $a_8 = 7(\sqrt{3})^{8-1} = 7(\sqrt{3})^7 \approx 327.358$.

Write an Expression for the Nth Term of the Geometric a1=7,r=3,n=8a _ { 1 } = 7 , r = \sqrt { 3 } , n = 8a1​=7,r=3​,n=8

Write an Expression for the Nth Term of the Geometric $a _ { 1 } = 7 , r = \sqrt { 3 } , n = 8$