Find the standard form of the equation of the ellipse with the given characteristics.
vertices: (-1, -11), (-1, 7), minor axis of length 2

A) $\frac { ( x + 1 ) ^ { 2 } } { 81 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$
B) $\frac { ( x + 2 ) ^ { 2 } } { 81 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$
C) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 81 } = 1$
D) $\frac { ( x - 2 ) ^ { 2 } } { 81 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1$
E) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y - 2 ) ^ { 2 } } { 81 } = 1$

Question

Find the standard form of the equation of the ellipse with the given characteristics.
vertices: (-1, -11), (-1, 7), minor axis of length 2

A) $\frac { ( x + 1 ) ^ { 2 } } { 81 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$
B) $\frac { ( x + 2 ) ^ { 2 } } { 81 } + \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$
C) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 81 } = 1$
D) $\frac { ( x - 2 ) ^ { 2 } } { 81 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1$
E) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y - 2 ) ^ { 2 } } { 81 } = 1$

Quizplus · Accepted Answer

The center of the ellipse is at (-1, -2), the major axis is vertical with length 18, and the minor axis is horizontal with length 2. The equation is $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 81 } = 1$.

Find the Standard Form of the Equation of the Ellipse (x+1)281+(y+2)24=1\frac { ( x + 1 ) ^ { 2 } } { 81 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 181(x+1)2​+4(y+2)2​=1

Find the Standard Form of the Equation of the Ellipse $\frac { ( x + 1 ) ^ { 2 } } { 81 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$