Find $\lim _ { x \rightarrow + \infty } \frac { 1 - 2 x } { 1 + 3 x }$ (if it exists).
A)0
B) $- \frac { 2 } { 3 }$
C) $\frac { 2 } { 3 }$
D)-$\infty$
E)does not exist

Question

Find $\lim _ { x \rightarrow + \infty } \frac { 1 - 2 x } { 1 + 3 x }$ (if it exists).  
A)0
B)  $- \frac { 2 } { 3 }$
C) $\frac { 2 } { 3 }$
D)-$\infty$
E)does not exist

Quizplus · Accepted Answer

To find the limit as $x$ approaches $+\infty$ for the given function $\frac{1 - 2x}{1 + 3x}$, we can divide the numerator and the denominator by $x$, the highest power of $x$ in the expression. This simplifies to $\frac{\frac{1}{x} - 2}{\frac{1}{x} + 3}$. As $x$ approaches $+\infty$, $\frac{1}{x}$ approaches 0, leaving us with $\frac{-2}{3}$.

Find lim⁡x→+∞1−2x1+3x\lim _ { x \rightarrow + \infty } \frac { 1 - 2 x } { 1 + 3 x }limx→+∞​1+3x1−2x​

Find $\lim _ { x \rightarrow + \infty } \frac { 1 - 2 x } { 1 + 3 x }$