Find $\lim _ { x \rightarrow 8 } \frac { 3 x } { \sqrt { x + 5 } }$ by direct substitution.
A) $\frac { 1 } { 8 }$
B) $0$
C) $24 \sqrt { 13 }$
D)1
E) $\frac { 24 } { \sqrt { 13 } }$

Name: Find $\lim _ { x \rightarrow 8 } \frac { 3 x } { \sqrt { x + 5 } }$ by direct substitution. A) $\frac { 1 } { 8 }$ B) $0$ C) $24 \sqrt { 13 }$ D)1 E) $\frac { 24 } { \sqrt { 13 } }$
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Question

Quizplus · Accepted Answer

By direct substitution, substitute $x = 8$ into the expression: $\frac{3 \times 8}{\sqrt{8 + 5}} = \frac{24}{\sqrt{13}}$.

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Find $\lim _ { x \rightarrow 8 } \frac { 3 x } { \sqrt { x + 5 } }$