A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a standard deviation of 11.Students who made 57.93 or lower on the exam failed the course.What percent of students failed the course?
A) 8.53%
B) 18.53%
C) 91.47%
D) 0.853%

Question

Quizplus · Accepted Answer

To find the percentage of students who failed, we calculate the z-score for 57.93 using the formula: z = (X - μ) / σ, where X is 57.93, μ is 73, and σ is 11. The z-score is approximately -1.36. Using the standard normal distribution table, a z-score of -1.36 corresponds to about 8.53% of students scoring below 57.93.

A Professor at a Local University Noted That the Exam