A box contains 3 red balls, 5 white balls, and 3 black balls. Two balls are drawn at random from the box with replacement of the first before the second is drawn.What is the probability of getting a red R ball on the first draw and a white W ball on the second?
A)Pr(R first ∩ W second) =
B)Pr(R first ∩ W second) =
C)Pr(R first ∩ W second) =
D)Pr(R first ∩ W second) =
E)Pr(R first ∩ W second) =

Question

A box contains 3 red balls, 5 white balls, and 3 black balls. Two balls are drawn at random from the box with replacement of the first before the second is drawn.What is the probability of getting a red R ball on the first draw and a white W ball on the second? ​
A)Pr(R first ∩ W second) = 
B)Pr(R first ∩ W second) = 
C)Pr(R first ∩ W second) = 
D)Pr(R first ∩ W second) = 
E)Pr(R first ∩ W second) =

Quizplus · Accepted Answer

The probability of drawing a red ball first is 3/11. 
Since the ball is replaced, the probability of drawing a white ball second is 5/11.
The probability of both events happening together is the product of the individual probabilities:
Pr(R first ∩ W second) = (3/11) x (5/11) = 15/121
Therefore, the correct answer is B.

A Box Contains 3 Red Balls, 5 White Balls, and 3