Suppose a box contains 7 defective transistors and 16 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is defective D and the second one is good G?
A)Pr(D first ∩ G second) =
B)Pr(D first ∩ G second) =
C)Pr(D first ∩ G second) =
D)Pr(D first ∩ G second) =
E)Pr(D first ∩ G second) =

Question

Suppose a box contains 7 defective transistors and 16 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is defective D and the second one is good G? ​
A)Pr(D first ∩ G second) = 
B)Pr(D first ∩ G second) = 
C)Pr(D first ∩ G second) = 
D)Pr(D first ∩ G second) = 
E)Pr(D first ∩ G second) =

Quizplus · Accepted Answer

The Answer of Suppose a box contains 7 defective transistors and 16 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is defective D and the second one is good G? ​
A)Pr(D first ∩ G second) = 
B)Pr(D first ∩ G second) = 
C)Pr(D first ∩ G second) = 
D)Pr(D first ∩ G second) = 
E)Pr(D first ∩ G second) =

Suppose a Box Contains 7 Defective Transistors and 16 Good