A group of printers were advertised in the Sunday supplement. The prices listed were $129, $275, $475, $139, $159, $210, $425, $159. What was the standard deviation from the
Mean to the nearest dollar:
A)$67
B)$346
C)$135
D)$246

Question

Quizplus · Accepted Answer

1. Calculate the mean: 
$129 + $275 + $475 + $139 + $159 + $210 + $425 + $159 = $1962 
$1962/8 = $245.25 
2. Calculate the variance: 
($129 - $245.25)^2 + ($275 - $245.25)^2 + ($475 - $245.25)^2 + ($139 - $245.25)^2 + ($159 - $245.25)^2 + ($210 - $245.25)^2 + ($425 - $245.25)^2 + ($159 - $245.25)^2 = 683469 
683469/8 = 85433.625 
3. Calculate the standard deviation: 
√85433.625 = 292.38 
Rounded to the nearest dollar, the standard deviation is $135.

A Group of Printers Were Advertised in the Sunday Supplement