A bottle of white wine at room temperature ( ) is placed in a refrigerator at 6 P.M.Its temperature after t hours is changing at the rate of . By how many degrees will the temperature of the wine have dropped by 10 P.M.? Please round your answer to one decimal place.
A)30.5
B)25.2
C)27.3
D)26.0

Question

A bottle of white wine at room temperature (  ) is placed in a refrigerator at 6 P.M.Its temperature after t hours is changing at the rate of   . By how many degrees will the temperature of the wine have dropped by 10 P.M.? Please round your answer to one decimal place.
A)30.5 
B)25.2 
C)27.3 
D)26.0

Quizplus · Accepted Answer

We can use the formula:
ΔT = k * t
where ΔT is the change in temperature, k is the rate of change, and t is the time elapsed.
From 6 P.M. to 10 P.M. is a total of 4 hours.
The change in temperature of the wine is:
ΔT = -0.13 * 4 = -0.52
This means the temperature of the wine would have dropped by 0.52 degrees Celsius.
Rounding this to one decimal place gives us 0.5 degrees Celsius.
Therefore, the temperature of the wine would have dropped by 0.5 degrees Celsius or approximately 0.9 degrees Fahrenheit.
The answer closest to this value is C)27.3 degrees Fahrenheit.

A Bottle of White Wine at Room Temperature