Question 1

In a mass spectrometer, chlorine ions of mass 35u and 37u, each with charge +5e, are emitted from a source and accelerated through a potential difference of 300 kV. They then enter at the same point) a region with a magnetic field of 0.20 T that is perpendicular to their original direction of motion. Calculate the separation between the two chlorine ions after they have made a half circle path in the magnetic field region. u = 1.66 × 10^-27 kg, e = 1.6 × 10^-19 C)

Accepted Answer

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Question 2

The radius of the orbit of an electron moving with a speed of 10⁸ m/s perpendicular to a magnetic field of 5.0 × 10^-3 T is approximately

Accepted Answer

The radius of the orbit can be calculated using the formula r = mv/qB. Using the given values: m (mass of electron) = 9.11 × 10^-31 kg, v = 10^8 m/s, q (charge of electron) = 1.6 × 10^-19 C, and B = 5.0 × 10^-3 T, the radius r is approximately 0.11 m.

Question 3

A wire of length L carries a current I, going from west to east, in the presence of a magnetic field B that is pointing vertically up. The wire moves a distance d to the south. The work done by the magnetic force on the moving charges is

Accepted Answer

The magnetic force does no work on the charges because it acts perpendicular to the direction of motion of the charges.

Question 4

An alpha particle with a charge 2e and mass 4m is moving with velocity v when it enters a magnetic field B at right angles to its direction of motion. A deuteron of charge e and mass 2m also enters the field in the same direction and the same speed. Calculate the difference in radius of motion between the alpha particle and the deuteron in the magnetic field region.

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Question 5

A negatively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

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Question 6

A positively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

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Question 7

5 T when a current of 1.3 A passes through the wire in a perpendicular direction to the magnetic field. Find the mass per unit length of the wire. The wire is connected to a battery by ultra light flexible leads.)

Accepted Answer

The magnetic force on the wire is equal to the gravitational force acting on it. Using the formula F = BIL = mg, where B = 5 T, I = 1.3 A, and g = 9.8 m/s², we solve for m/L (mass per unit length): m/L = (BIL)/g = (5 * 1.3)/9.8 = 0.20 kg/m.

Question 8

A beam of charged particles moving with a speed of 10⁶ m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion. If the particles move in a radius of 0.2 m, then calculate their period of motion.

Accepted Answer

The period of motion can be calculated using the equation T = 2πm/(qB), where m is the mass of the particle, q is its charge, and B is the magnetic field. In this case, we are not given the mass or charge of the particles, but we know that they are all moving with the same velocity, so we can assume that they have the same mass and charge.

Using the given radius and speed, we can calculate the magnetic field strength required to create the observed circular motion using the equation B = mv/(qr), where r is the radius of the circular path.

Plugging in the given values, we get B = (m)(10^16)/(q)(0.2), or B = 50m/q, where we have converted the velocity to meters per second.

Since we are told that the magnetic field is 0.1 T, we can equate these two expressions for B and solve for m/q:

0.1 T = 50m/q 
m/q = (0.1 T)/(50) = 2 × 10^-3 kg/C

Now we can plug this value for m/q into the equation for the period of motion:

T = 2πm/(qB) = 2π(m/q)/(B) = 2π/(B(m/q))

Substituting in the known values, we get T = 2π/(0.1 T)(2 × 10^-3 kg/C) = 1.3 × 10^-6 s, or C.

Question 9

In a mass spectrometer, ions of nickel with mass 9.62 × 10^-26 kg and charge +2e are accelerated through a potential difference of X volts and then deflected in a magnetic field of 0.15 T. If the radius of curvature of the ions is 0.55 m, then calculate the value of the potential difference X.

Accepted Answer

The potential difference X can be calculated using the formula for the radius of curvature in a magnetic field: r = (mv)/(qB). The velocity v can be found from the kinetic energy gained by the ions: qX = 0.5mv^2. Solving these equations gives X = 11.3 kV.

Question 10

An electric field of 3.0 kV/m is perpendicular to a magnetic field of 0.20 T. An electron moving in a direction perpendicular to both E and B is not deflected if it has a velocity of

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Question 11

A small permanent magnet is placed in a uniform magnetic field of magnitude 0.35 T. If the maximum torque experienced by the magnet is 0.50 N · m, what is the magnitude of the magnetic moment  ) of the magnet  )?

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Question 12

A 30 cm long wire with an east-west orientation carries a current of 3.0 A westward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

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Question 13

In a mass spectrometer, chlorine ions of mass 35u and charge +5e are emitted from a source and accelerated through a potential difference of 250 kV. They then enter a region with a magnetic field that is perpendicular to their original direction of motion. The chlorine ions exit the spectrometer after being bent along a path with a radius of curvature 3.5 m. What is the speed of the chlorine ions as they enter the magnetic field region u = 1.66 × 10^-27 kg, e = 1.6 × 10^-19 C)?

Accepted Answer

The speed of the ions can be calculated using the energy equation: $ qV = \frac{1}{2}mv^2 $. Solving for $ v $, we get $ v = \sqrt{\frac{2qV}{m}} $. Substituting the given values: $ q = 5e = 5 \times 1.6 \times 10^{-19} \, \text{C} $, $ V = 250 \times 10^3 \, \text{V} $, and $ m = 35 \times 1.66 \times 10^{-27} \, \text{kg} $, we find $ v \approx 2.6 \times 10^6 \, \text{m/s} $.

Question 14

A beam of electrons moving at a speed of 8 × 10⁴ m/s is undeflected when it passes through an electric field of 5 N/C perpendicular to its path and a magnetic field that is perpendicular to its path and also to that of the electric field. Calculate the strength of the magnetic field.

Accepted Answer

The magnetic force must equal the electric force for the beam to be undeflected. Using the formula F = qE = qvB, we find B = E/v = 5 N/C / (8 × 10^4 m/s) = 6.25 × 10^-5 T.

Question 15

A 3.0-m long straight wire segment makes an angle of 28º with a uniform magnetic field of 1.0 T. The magnitude of the force on the wire if it carries a current of 1.5 A is approximately

Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). Substituting the given values: I = 1.5 A, L = 3.0 m, B = 1.0 T, and θ = 28º, we get F = 1.5 * 3.0 * 1.0 * sin(28º) ≈ 2.1 N.

Question 16

In a mass spectrometer, chlorine ions of mass 35u and charge +5e are emitted from a source and accelerated through a potential difference of 250 kV. They then enter a region with a magnetic field, which is perpendicular to their original direction of motion. The chlorine ions exit the spectrometer after being bent along a path with a radius of curvature 3.5 m. What is the value of the magnetic field u = 1.66 × 10^-27 kg, e = 1.6 × 10^-19 C)?

Accepted Answer

The answer of In a mass spectrometer, chlorine ions of...

Question 17

A rectangular loop of wire 0.10 m by 0.20 m) carries a current of 5.0 A in a counterclockwise direction. The loop is oriented as shown in a uniform magnetic field of 1.5 T. The force acting on the upper 0.10-m side of the loop is

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Question 18

A current I flows in a wire that is oriented as shown. The vector representing the magnetic field that results in a maximum force on the wire is

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According to the right hand rule, if the thumb points in the direction of the current (to the right in this case), the fingers will curl in the direction of the magnetic field. Choice 3 shows the magnetic field lines curling around the wire in the correct direction to create a maximum force on the wire.

Question 19

A long straight wire parallel to the y-axis carries a current of 6.3 A in the positive y direction. There is a uniform magnetic field B = 1.5 T along the positive x direction. The magnitude of the force per unit length on the wire is approximately

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Question 20

A 30-cm long wire with an east-west orientation carries a current of 3.0 A eastward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

Accepted Answer

The force on the wire is given by the formula F = BIL sinθ, where B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field. In this case, θ = 90° because the magnetic field is perpendicular to the wire. So, we have:

0.18 N = B(3.0 A)(0.30 m) sin 90°

Solving for B, we get:

B = 0.20 T north

Quiz 19: Magnetism

The radius of the orbit of an electron moving with a speed of 10⁸ m/s perpendicular to a magnetic field of 5.0 × 10^-3 T is approximately

A wire of length L carries a current I, going from west to east, in the presence of a magnetic field B that is pointing vertically up. The wire moves a distance d to the south. The work done by the magnetic force on the moving charges is

A negatively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

A positively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

5 T when a current of 1.3 A passes through the wire in a perpendicular direction to the magnetic field. Find the mass per unit length of the wire. The wire is connected to a battery by ultra light flexible leads.)

A beam of charged particles moving with a speed of 10⁶ m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion. If the particles move in a radius of 0.2 m, then calculate their period of motion.

In a mass spectrometer, ions of nickel with mass 9.62 × 10^-26 kg and charge +2e are accelerated through a potential difference of X volts and then deflected in a magnetic field of 0.15 T. If the radius of curvature of the ions is 0.55 m, then calculate the value of the potential difference X.

An electric field of 3.0 kV/m is perpendicular to a magnetic field of 0.20 T. An electron moving in a direction perpendicular to both E and B is not deflected if it has a velocity of

A small permanent magnet is placed in a uniform magnetic field of magnitude 0.35 T. If the maximum torque experienced by the magnet is 0.50 N · m, what is the magnitude of the magnetic moment ) of the magnet ) ?

A 30 cm long wire with an east-west orientation carries a current of 3.0 A westward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

A beam of electrons moving at a speed of 8 × 10⁴ m/s is undeflected when it passes through an electric field of 5 N/C perpendicular to its path and a magnetic field that is perpendicular to its path and also to that of the electric field. Calculate the strength of the magnetic field.

A 3.0-m long straight wire segment makes an angle of 28º with a uniform magnetic field of 1.0 T. The magnitude of the force on the wire if it carries a current of 1.5 A is approximately

A rectangular loop of wire 0.10 m by 0.20 m) carries a current of 5.0 A in a counterclockwise direction. The loop is oriented as shown in a uniform magnetic field of 1.5 T. The force acting on the upper 0.10-m side of the loop is

A current I flows in a wire that is oriented as shown. The vector representing the magnetic field that results in a maximum force on the wire is

A long straight wire parallel to the y-axis carries a current of 6.3 A in the positive y direction. There is a uniform magnetic field B = 1.5 T along the positive x direction. The magnitude of the force per unit length on the wire is approximately

A 30-cm long wire with an east-west orientation carries a current of 3.0 A eastward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

Quiz 19: Magnetism

The radius of the orbit of an electron moving with a speed of 108 m/s perpendicular to a magnetic field of 5.0 × 10-3 T is approximately

A wire of length L carries a current I, going from west to east, in the presence of a magnetic field B that is pointing vertically up. The wire moves a distance d to the south. The work done by the magnetic force on the moving charges is

A negatively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

A positively charged particle is moving through uniform fields E and B, which are directed in the positive x and positive y directions, respectively. If there is no resultant force on the particle, then its velocity is in the

5 T when a current of 1.3 A passes through the wire in a perpendicular direction to the magnetic field. Find the mass per unit length of the wire. The wire is connected to a battery by ultra light flexible leads.)

A beam of charged particles moving with a speed of 106 m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion. If the particles move in a radius of 0.2 m, then calculate their period of motion.

In a mass spectrometer, ions of nickel with mass 9.62 × 10-26 kg and charge +2e are accelerated through a potential difference of X volts and then deflected in a magnetic field of 0.15 T. If the radius of curvature of the ions is 0.55 m, then calculate the value of the potential difference X.

An electric field of 3.0 kV/m is perpendicular to a magnetic field of 0.20 T. An electron moving in a direction perpendicular to both E and B is not deflected if it has a velocity of

A small permanent magnet is placed in a uniform magnetic field of magnitude 0.35 T. If the maximum torque experienced by the magnet is 0.50 N · m, what is the magnitude of the magnetic moment ) of the magnet ) ?

A 30 cm long wire with an east-west orientation carries a current of 3.0 A westward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

A beam of electrons moving at a speed of 8 × 104 m/s is undeflected when it passes through an electric field of 5 N/C perpendicular to its path and a magnetic field that is perpendicular to its path and also to that of the electric field. Calculate the strength of the magnetic field.

A 3.0-m long straight wire segment makes an angle of 28º with a uniform magnetic field of 1.0 T. The magnitude of the force on the wire if it carries a current of 1.5 A is approximately

A rectangular loop of wire 0.10 m by 0.20 m) carries a current of 5.0 A in a counterclockwise direction. The loop is oriented as shown in a uniform magnetic field of 1.5 T. The force acting on the upper 0.10-m side of the loop is

A current I flows in a wire that is oriented as shown. The vector representing the magnetic field that results in a maximum force on the wire is

A long straight wire parallel to the y-axis carries a current of 6.3 A in the positive y direction. There is a uniform magnetic field B = 1.5 T along the positive x direction. The magnitude of the force per unit length on the wire is approximately

A 30-cm long wire with an east-west orientation carries a current of 3.0 A eastward. There is a uniform magnetic field perpendicular to this wire. If the force on the wire is 0.18 N upward, what are the direction and magnitude of the magnetic field?

The radius of the orbit of an electron moving with a speed of 10⁸ m/s perpendicular to a magnetic field of 5.0 × 10^-3 T is approximately

A beam of charged particles moving with a speed of 10⁶ m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion. If the particles move in a radius of 0.2 m, then calculate their period of motion.

In a mass spectrometer, ions of nickel with mass 9.62 × 10^-26 kg and charge +2e are accelerated through a potential difference of X volts and then deflected in a magnetic field of 0.15 T. If the radius of curvature of the ions is 0.55 m, then calculate the value of the potential difference X.

A beam of electrons moving at a speed of 8 × 10⁴ m/s is undeflected when it passes through an electric field of 5 N/C perpendicular to its path and a magnetic field that is perpendicular to its path and also to that of the electric field. Calculate the strength of the magnetic field.